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How much current will an electric bulb draw from a 220 V source, if the resistance of the bulb filament is 1200 ??

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Given, Voltage, V=220V and Resistance, R=1200 ohm, as we know V=IR I=V/R=220/1200=0.1833A
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The formulula to be used is IR =V So I = V/R = 220/1200 = 0.1833 Amp
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