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Are tuitions mandatory in the class 10 CBSE to score a 98%?

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Ability to solve Problems in maths ,makes you Strong enough to solve your Problems in Life

Not mandatory,Tution only helps to boosts you .You must have consistency and confidence in your preparation
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Account teacher. I teach Account in very simple and interesting...

Not at all,it's depdend on you .
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Working on quality mathematics Content

It is not necessary if students is good ,
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Try to understand Physics and Maths concepts easily with me.

It is easy to get that dream come true if you have guidance. Although no one can give you,it needs your effort.
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Not actually, provided the teachers are skilled and students are desciplined
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Yoga professional teacher with 3 year of experience

It's not mandatory if you are a good student and also you have a good teacher
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No, not at all. But everyone should try to get the best . So if after giving your best , you're just getting 95% or whatsoever then there's nothing wrong in that but the thing is that everyone should try their best to get good results.
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If you are much dedicated and work hard ,you can score high marks by studying your ncert text thoroughly and by working out previous year questions
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If you are not a self learner then it is mandatory for you to take a tuition.
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Not really. If you understand things by yourself then self study is enough. You just need to practice answer writing on timed tests.
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Related Questions

In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.
Let the marks of mathematics be x Than marks of science be 28-x now according to question (x+3), (28-x-4) The product of new marks will be 180 So, (x+3) (28-x-4)=180 24x-x^2+72-3x=180 x^2-21x+108=0 x^2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 (x-9)=0...
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Magnification produced by a plane mirror is +1. It means the size of the image is equal to the size of the object and the image is virtual. Size of image is equal to size of object
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