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Let the two numbers be "x" and "y" such that x>y
Hence original digit is 10x+y, & reversed digit is 10y+x
By the condition of the problem
(10x+y)+ (10y+x)= 165
11x+11y=165............(1)
x-y =3............(2)
x+y=15............(1) divided by 11 on both sides.......(3)
Adding equation (2) and (3)
2x =18
x=9
y=6
therefore the two digit number is 96 and the reverse order number is 69
so you can see that 96+69=165 and 9-6=3.......satisfies the condition of the question.
......... All the best.................
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The two numbers can be any unknown variables. We will take x and y.
Reversing 165, we get 561 which means that adding them will give me 561.
Subtracting the two I will get 3. Conveting them to equations we get
x+y =561
x-y = 3
Adding the two equations we get
2x=564
x=282
Substituting the value of x in (x-y=3)
282-y=3
Therefoe, y=279
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