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Represent the following situations in the form of quadratic equations:

(i) The area of a rectangular plot is 528 . The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.

(ii) The product of two consecutive positive integers is 306. We need to find the integers.

(iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan’s present age.

(iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.

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I have a degree in Mechanical Engineering I have conducted over 12000 online sessions on Math. durin

(i) If breadth =x, length=2x+1, area= length X breadth= Simplifying Factorising (2x +33)(x-16)=0, x= Rejecting the negative value, so x=16 Substituting, 2x+1=2x16+1=33 So breadth=16m, length=33m (ii) Let the two consecutive numbers be x and (x+1) (x-17)(x-18)=0, so x=17, 18,consecutive integers...
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(i) If breadth =x,

length=2x+1,

area= length X breadth= 

Simplifying 

Factorising (2x +33)(x-16)=0,

x=

 Rejecting the negative value, so  x=16 

Substituting, 2x+1=2x16+1=33

So breadth=16m, length=33m

(ii) Let the two consecutive numbers be x and (x+1)

(x-17)(x-18)=0,

so x=17, 18,consecutive integers are 17,18 as their product is 306

(iii) If Rohan's present age=x,

his mother's age=x+26,

3 years from now, their ages will be  x+3 and and x+29,

So product=(x+3)(x+29)=360

(x+39)(x-7)=0. x= -39, x= 7

Rejecting negative value

x=7,x+26=7+26=33,So Rohan's  present age=7 years

v) If the speed of train is xkm/hr.

Then time to travel 480km. is 480/x hour. 

Speed X time= Distance 

and with a speed of (x-8) km/hr,time=480/(x-8)hr.

So 480/(x-8)= (480/x)+3,

After simplifying we get 

solving we get x=40,-32,

rejecting negative value

speed of the train=40km/hr.

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Maths and Science Grade 8-10 SSC and CBSE tuitions

1)2b^2+b-528=0 2)n^2+n-306=0 3)x^2+32x-273=0 4)x^2-8x-1280=0
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Tutor

Let breadth of plot is x Hence length of plot = 2x + 1 Area of Plot = (2x+1)x Now (2x+1)x = 528 OR 2x2 + x - 528 = 0 This is the required quadratic equation.
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An Engineer

(i) x(2x+1)=528 (ii) x(x+1)=306 (iii) (x+3)(x+29)=360 (iv) (480/(x-8)) - (480/x)=3
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I have a degree in Mechanical Engineering I have conducted over 12000 online sessions on Math. durin

(i) If breadth =x,length=2x+1,area=lengthxbreadth=(2x+1)*x=528 Simplifying 2x^2+x-528=0,Factorising (2x +33)(x-16)=0,x=-33/2,16, Rejecting negative value x=16 so 2x+1=2x16+1=33 So breadth=16m, length=33m.
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