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Prove that  is irrational.

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Let is a rational number. Therefore. we can find two integers a, b (b 0)such that = Let a and b have a common factor other than 1. Then we can dividethem by the common factor. and assume that a and b are co-prime.a = = Therefore. is divisible by 5 and it can be said that a is divisible by 5. Let...
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Let is a rational number. Therefore. we can find two integers a, b (b  0)
such that   =
Let a and b have a common factor other than 1. Then we can divide
them by the common factor. and assume that a and b are co-prime.
a =
=
Therefore. is divisible by 5 and it can be said that a is divisible by 5. Let a
= 5k. where k is an integer
=
= This mans that is divisible by 5 and hence, b is divisible
by 5.
This implies that a and b have 5 as a common factor. And this is a
contradiction to the fact that a and b are co-prime.
Hence, cannot be expressed as  and it can be said that  is irrational.

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I have 8 year experience in teaching.

Because the value of √5 is not terminate and not recurring
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Experienced Mathematics Teacher

It can't be expressed in p/q form, p and q being integers.
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Teaching since 2018 (9-12 Maths Physics) in Institute

Since √5=2.236067977........so it is a non-terminating. And non-recurring too...so it is an irrational number .
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I have a degree in Mechanical Engineering I have conducted over 12000 online sessions on Math. durin

Let√5 is a rational number.So √5=a/b, squaring both sides 5=a^2/b^2 and a^2=5b^2,So a^2 is divisible by 5. Hence a is also divisible by 5. Let a =5c where c is an integer. Then a^2=5b^2=25c^2 b^2=5c^2. So b^2 is divisible by 5. Hence b is also divisible by 5. So and b have a common factor5.But...
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Let√5 is a rational number.So  √5=a/b, squaring both sides 5=a^2/b^2 and a^2=5b^2,So a^2 is divisible by 5.

Hence a is also divisible by 5. Let a =5c where c is an integer. Then a^2=5b^2=25c^2

b^2=5c^2. So b^2 is divisible by 5. Hence b is also divisible by 5. So and b have a common factor5.But for a rational number a/b ,common factor between a and b cannot be other than 1.So this contradicts √5 is a rational number. So √5 is irrational.

 

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Related Questions

Prove that 3+2 is irrational.
To prove : 3+2√5 is rational number. Ans: 3 is rational number. 2 is rational number. 2√5 is irrational number (product of rational and irrational is an irrational number) 3+2√5 is an...
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