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Asked by Sujeet Last Modified
Answer 
Yasaswi Nath
Tutor
m = tanX + sinX
n = tanX - sinX
m2-n2 = (tanX + sinX)2 - (tanX - sinX)2 = tan2X + sin2X + 2tanX.sinX - tan2X - sin2X +2tanX.sinX
m2-n2 = 4tanX.sinX
now mn = (tanX + sinX).(tanX - sinX)
mn = tan2X - sin2X = (sin2X/cos2X) - sin2X = sin2X((1/cos2X) -1) = sin2X((1-cos2X)/cos2X)
= sin2X. (sin2X/
read less Yasaswi Nath
Tutor
m = tanX + sinX
n = tanX - sinX
m2-n2 = (tanX + sinX)2 - (tanX - sinX)2 = tan2X + sin2X + 2tanX.sinX - tan2X - sin2X +2tanX.sinX
m2-n2 = 4tanX.sinX
now, mn = (tanX + sinX).(tanX - sinX)
mn = tan2X - sin2X = (sin2X/cos2X) - sin2X = sin2X((1/cos2X) -1) = sin2X((1-cos2X)/cos2X)
= sin2X. (sin2X/cos2X) = sin2X.tan2X
(mn)1/2 = sinX.tanX
We know that, m2-n2 = 4tanX.sinX
now replacing "tanX.sinX",
m2-n2 = 4(mn)1/2
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