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Why does C treat array parameters as pointers?

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In C, array parameters are treated as pointers. The following two definitions of foo() look different, but to the compiler they mean exactly the same thing. Itâ??s preferable to use whichever syntax is more accurate for readability. If the pointer coming in really is the base address of a whole array,...
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In C, array parameters are treated as pointers. The following two definitions of foo() look different, but to the compiler they mean exactly the same thing. Itâ??s preferable to use whichever syntax is more accurate for readability. If the pointer coming in really is the base address of a whole array, then we should use [ ]. void foo(int arr_param[]) { /* Silly but valid. Just changes the local pointer */ arr_param = NULL; } void foo(int *arr_param) { /* ditto */ arr_param = NULL; } read less
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