Program to accept a list of elements and find the maximum number in the list.

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The logic will be 1. Create an array of the desired type 2. Sort the array in the descending order 3. Fetch the first elemnet from the array, this will be the maximum element in that array. Now use this logic to write code in the desired programming language.
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The logic will be 1. Create an array of the desired type 2. Sort the array in the descending order 3. Fetch the first elemnet from the array, this will be the maximum element in that array. Now use this logic to write code in the desired programming language. read less
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#include<stdio.h> int main() { int a,i,n,large,small; printf("How many elements:"); scanf("%d",&n); printf("Enter the Array:"); for(i=0;i<n;++i) scanf("%d",&a); large=small=a; for(i=1;i<n;++i) { if(a>large) ...
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#include<stdio.h> int main() { int a[50],i,n,large,small; printf("How many elements:"); scanf("%d",&n); printf("Enter the Array:"); for(i=0;i<n;++i) scanf("%d",&a[i]); large=small=a[0]; for(i=1;i<n;++i) { if(a[i]>large) large=a[i]; if(a[i]<small) small=a[i]; } printf("The largest element is %d",large); printf("\nThe smallest element is %d",small); return 0; } read less
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using System; using System.Linq; public class abc { // returns maximum in arr of size n static int MaximumNumber(int arr, int n) { return arr.Max(); } static public void Main () { int arr = {10, 324, 45, 90, 9808}; int n = arr.Length; ...
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using System; using System.Linq; public classabc{ // returns maximum in arr[] of size n static intMaximumNumber(int []arr, int n) { return arr.Max(); } static public void Main () { int []arr = {10, 324, 45, 90, 9808}; int n = arr.Length; Console.WriteLine( MaximumNumber(arr, n)); } } read less
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C programming code #include <stdio.h> int main() { int array, maximum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d", &size); printf("Enter %d integers\n", size); for (c = 0; c < size; c++) ...
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C programming code #include <stdio.h> int main() { int array[100], maximum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d", &size); printf("Enter %d integers\n", size); for (c = 0; c < size; c++) scanf("%d", &array[c]); maximum = array[0]; for (c = 1; c < size; c++) { if (array[c] > maximum) { maximum = array[c]; location = c+1; } } printf("Maximum element is present at location %d and it's value is %d.\n", location, maximum); return 0; } read less
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C programming code #include <stdio.h> int main() { int array, maximum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d", &size); printf("Enter %d integers\n", size); for (c = 0; c < size; c++) ...
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C programming code #include <stdio.h> int main() { int array[100], maximum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d", &size); printf("Enter %d integers\n", size); for (c = 0; c < size; c++) scanf("%d", &array[c]); maximum = array[0]; for (c = 1; c < size; c++) { if (array[c] > maximum) { maximum = array[c]; location = c+1; } } printf("Maximum element is present at location %d and it's value is %d.\n", location, maximum); return 0; } read less
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Use Max heap, every time accept a number and perform heapify operation. In the end, the element at root will be maximum. Time complexity, O(nlogn).
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# include<stdio.h> #include< conio.h> void main () { int a,n,i ,max; printf( " Enter no. of elements"); scanf("%d",&n); printf ("Enter all elements one by one"); for(I=0;I<n;I++) scanf("%d",&a); max=a; for( i=0; i<n; i++) { If( a>max) max= a; } printf...
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# include<stdio.h> #include< conio.h> void main () { int a[50],n,i ,max; printf( " Enter no. of elements"); scanf("%d",&n); printf ("Enter all elements one by one"); for(I=0;I<n;I++) scanf("%d",&a[i]); max=a[ 0 ]; for( i=0; i<n; i++) { If( a[ i ]>max) max= a[ i ]; } printf ("Largest element: %d",max); getch(); } read less
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