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C Language > Learn C Language > How do I swap n number of strings in C programming?
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How do I swap n number of strings in C programming?

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void swap34(float *ptr1, float *ptr2); void main() { float x; int i, n; printf("How many Elements...\n"); scanf("%d", &n); printf("Enter Elements one by one\n"); for (i = 0; i < n; i++) { scanf("%f", x + i); } /* Function call:Interchanging...
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void swap34(float *ptr1, float *ptr2); void main() { float x[10]; int i, n; printf("How many Elements...\n"); scanf("%d", &n); printf("Enter Elements one by one\n"); for (i = 0; i < n; i++) { scanf("%f", x + i); } /* Function call:Interchanging 3rd element by 4th */ swap34(x + 2, x + 3); printf("\nResultant Array...\n"); for (i = 0; i < n; i++) { printf("X[%d] = %f\n", i, x[i]); } } /* Function to swap the 3rd element with the 4th element in the array */ void swap34(float *ptr1, float *ptr2 ) { float temp; temp = *ptr1; *ptr1 = *ptr2; *ptr2 = temp; } read less
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swapping means changing the places first include header files and write the body of a program and then decleare the string syntax then output
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Advance Excel And VBA Training

If you want to swap a number of string then it will be a char array length equals to number of digits. Then its pretty simple you just need to run a for loop starting from i=0 to i read more
If you want to swap a number of string then it will be a char array length equals to number of digits. Then its pretty simple you just need to run a for loop starting from i=0 to iread less
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