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Asked by Mukesh Last Modified
Answer To overload an operator, we use a special operator function. We define the function inside the class or structure whose objects/variables we want the overloaded operator to work with. class className { ... .. ... public returnType operator symbol (arguments) { ... .. ... } ... .. ... };
int a; float b,sum; sum = a + b;read less
Here, variables “a” and “b” are of types “int” and “float”, which are built-in data types. Hence the addition operator ‘+’ can easily add the contents of “a” and “b”. This is because the addition operator “+” is predefined to add variables of built-in data type only.
Operator overloading is a compile-time polymorphism. It is an idea of giving special meaning to an existing operator in C++ without changing its original meaning.
In C++, we can make operators work for user-defined classes. This means C++ has the ability to provide the operators with a special meaning for a data type, this ability is known as operator overloading. For example, we can overload an operator ‘+’ in a class like String so that we can concatenate two strings by just using +. Other example classes where arithmetic operators may be overloaded are Complex Numbers, Fractional Numbers, Big integers, etc.
read lessRelated Questions
What is the main difference between returning value of a function and does not return any value of a function in C. Which is correct void main(void), int main(void), int main(int) , or void main(int) and explain the main difference between int main() and int main(void).
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