How can you convert hexadecimal to binary without using arrays or strings in a C program?

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Simple just use switch case int main() { char binarynum, hexa; long int i = 0; printf("Enter the value for hexadecimal "); scanf("%s", hexa); printf("\n Equivalent binary value: "); while (hexa) { switch (hexa) { case '0': ...
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Simple just use switch case int main() { char binarynum[MAX], hexa[MAX]; long int i = 0; printf("Enter the value for hexadecimal "); scanf("%s", hexa); printf("\n Equivalent binary value: "); while (hexa[i]) { switch (hexa[i]) { case '0': printf("0000"); break; case '1': printf("0001"); break; case '2': printf("0010"); break; case '3': printf("0011"); break; case '4': printf("0100"); break; case '5': printf("0101"); break; case '6': printf("0110"); break; case '7': printf("0111"); break; case '8': printf("1000"); break; case '9': printf("1001"); break; case 'A': printf("1010"); break; case 'B': printf("1011"); break; case 'C': printf("1100"); break; case 'D': printf("1101"); break; case 'E': printf("1110"); break; case 'F': printf("1111"); break; case 'a': printf("1010"); break; case 'b': printf("1011"); break; case 'c': printf("1100"); break; case 'd': printf("1101"); break; case 'e': printf("1110"); break; case 'f': printf("1111"); break; default: printf("\n Invalid hexa digit %c ", hexa[i]); return 0; } i++; } return 0; } read less
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#include int main(){ int n, i, j, bin_rev=0,bin=0; printf("Enter a number to convert : "); scanf("%d",&n); /*****************************/ i=1; while(n){ bin_rev=bin_rev+(n%2)*i; i=i*10; n=n/2; } i=1; while(bin_rev){ bin=bin+(bin_rev%10)*i; i=i*10; bin_rev=bin_rev/10; ...
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#include int main(){ int n, i, j, bin_rev=0,bin=0; printf("Enter a number to convert : "); scanf("%d",&n); /*****************************/ i=1; while(n){ bin_rev=bin_rev+(n%2)*i; i=i*10; n=n/2; } i=1; while(bin_rev){ bin=bin+(bin_rev%10)*i; i=i*10; bin_rev=bin_rev/10; } /*****************************/ printf("nBinary is %d",bin); getch(); return 0; } read less
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