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Aditya S jQuery trainer in Bangalore

Aditya S

Web technologies Trainer

Kasturi Nagar, Bangalore, India - 560016.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Aditya S describes himself as Web technologies Trainer. He conducts classes in Angular.JS, HTML and Java Script Training. Aditya is located in Kasturi Nagar, Bangalore. Aditya takes Online Classes- via online medium. He has 8 years of teaching experience . He is well versed in Hindi, English and Telugu.

Languages Spoken

Hindi

English

Telugu

Address

Kasturi Nagar, Bangalore, India - 560016

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Teaches

jQuery Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in jQuery Training

8

HTML Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in HTML Training

8

Java Training Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Java Training Classes

8

Teaches

Servlet, Core Java, JSP (Java Server Pages)

Java Script Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Java Script Training classes

8

Angular.JS Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Angular.JS, HTML, Java Script Training, Java Training and jQuery Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 8 years.

Answers by Aditya S (2)

Answered on 30/07/2016 Learn IT Courses/Java

String objects cannot be changed once they are created. Ex: String s1 = "abc"; s1 = s1+"def"; Now the reference s1 refers to the string "abcdef". But the string "abc" which is created earlier is not modified. It still exists in a string pool. Instead a new string is created which is "abcdef" and its... ...more
String objects cannot be changed once they are created. Ex: String s1 = "abc"; s1 = s1+"def"; Now the reference s1 refers to the string "abcdef". But the string "abc" which is created earlier is not modified. It still exists in a string pool. Instead a new string is created which is "abcdef" and its referred by s1. Now if s1 was StringBuffer or a StringBuilder, Ex: StringBuffer sb = new StringBuffer("abc"); sb= sb.append("def"); "abc" gets modified to "abcdef". Therefore its only one object which is created and that itself gets modified. The StringBuffer is thread safe and hence the operations are slow compared to StringBuilder. Hope this helps.
Answers 26 Comments
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Answered on 30/07/2016 Learn IT Courses/Java

Sometimes there will be a few activities which have to be done after a piece of code gets executed. For example closing a connection to a database. This activity has to be done irrespective of whether a piece of code gets executed successfully or throws an exception. Because the connection has to release... ...more
Sometimes there will be a few activities which have to be done after a piece of code gets executed. For example closing a connection to a database. This activity has to be done irrespective of whether a piece of code gets executed successfully or throws an exception. Because the connection has to release the database resources. 'Finally' block in java gets executed irrespective of whether the enclosed code in the try block gets executed successfully or throws an exception. So the code to close the DB connection can be written in finally block because it is guaranteed to be executed whether the code in try block gets executed with or without exception.
Answers 23 Comments
Dislike Bookmark

Teaches

jQuery Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in jQuery Training

8

HTML Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in HTML Training

8

Java Training Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Java Training Classes

8

Teaches

Servlet, Core Java, JSP (Java Server Pages)

Java Script Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Java Script Training classes

8

Angular.JS Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

No Reviews yet!

Answers by Aditya S (2)

Answered on 30/07/2016 Learn IT Courses/Java

String objects cannot be changed once they are created. Ex: String s1 = "abc"; s1 = s1+"def"; Now the reference s1 refers to the string "abcdef". But the string "abc" which is created earlier is not modified. It still exists in a string pool. Instead a new string is created which is "abcdef" and its... ...more
String objects cannot be changed once they are created. Ex: String s1 = "abc"; s1 = s1+"def"; Now the reference s1 refers to the string "abcdef". But the string "abc" which is created earlier is not modified. It still exists in a string pool. Instead a new string is created which is "abcdef" and its referred by s1. Now if s1 was StringBuffer or a StringBuilder, Ex: StringBuffer sb = new StringBuffer("abc"); sb= sb.append("def"); "abc" gets modified to "abcdef". Therefore its only one object which is created and that itself gets modified. The StringBuffer is thread safe and hence the operations are slow compared to StringBuilder. Hope this helps.
Answers 26 Comments
Dislike Bookmark

Answered on 30/07/2016 Learn IT Courses/Java

Sometimes there will be a few activities which have to be done after a piece of code gets executed. For example closing a connection to a database. This activity has to be done irrespective of whether a piece of code gets executed successfully or throws an exception. Because the connection has to release... ...more
Sometimes there will be a few activities which have to be done after a piece of code gets executed. For example closing a connection to a database. This activity has to be done irrespective of whether a piece of code gets executed successfully or throws an exception. Because the connection has to release the database resources. 'Finally' block in java gets executed irrespective of whether the enclosed code in the try block gets executed successfully or throws an exception. So the code to close the DB connection can be written in finally block because it is guaranteed to be executed whether the code in try block gets executed with or without exception.
Answers 23 Comments
Dislike Bookmark

Aditya S describes himself as Web technologies Trainer. He conducts classes in Angular.JS, HTML and Java Script Training. Aditya is located in Kasturi Nagar, Bangalore. Aditya takes Online Classes- via online medium. He has 8 years of teaching experience . He is well versed in Hindi, English and Telugu.

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