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Chandrakanth Class 9 Tuition trainer in Hyderabad

Chandrakanth

Engineering Tutor

Borabanda Parvathi Nagar, Hyderabad, India - 500072.

1 Student

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

English

Telugu

Hindi

Education

Matrusree engineering college 2017

Bachelor of Technology (B.Tech.)

Address

Borabanda Parvathi Nagar, Hyderabad, India - 500072

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Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Telugu, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Social Science, Telugu, Science, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Telugu, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Social Science, Telugu, Science, Mathematics

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Kinematics of Machinery, Internal Combustion Engines and Emissions, Dynamics of Machinery, Plant Layout and Material Handling, Finite Element Analysis, Fluid Mechanics, Automotive Fuels and Fuel Sysytems, Metrology, Mechanical Measurements and Instrumentation, Heat & Mass Transfer, Operations Research, Manufacturing Technology, Composites: Mechanics & Processing, Machine Design, Heat Treatment of Metals and Alloys, Mechanics of Machines, Welding Technology, Machine Dynamics and Vibrations/ Acoustics, Turbomachines, Machine Tool Technology, Thermodynamics, Analysis and Design of Machine Components, Refrigeration & Air Conditioning Systems, Jet Propulsion and Rocket Technology, Steam & Gas Turbines, Electronic Mesurement & Instrumentation, Strength of Materials, Material Science and Metallurgy

BTech Branch

BTech Automobile Engineering, BTech 1st Year Engineering, BTech Mechanical Engineering

BTech Automobile subjects

Measurement And Metrology & Instrumentation, Theory Of Machines, Mechanics Of Machines, Design Of Machine Elements, Engineering Mechanics, Thermodynamics, Strength Of Materials

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Advanced Mathematics (M2), Engineering Graphics, Basic Electronics, Engineering Physics, Environmental Studies, Mechanics Of Solids, Basic Mechanical Engineering, Engineering Mathematics (M1), Engineering Chemistry

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, State

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Telugu, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Social Science, Telugu, Science, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE, State

CBSE Subjects taught

Telugu, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Social Science, Telugu, Science, Mathematics

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Kinematics of Machinery, Internal Combustion Engines and Emissions, Dynamics of Machinery, Plant Layout and Material Handling, Finite Element Analysis, Fluid Mechanics, Automotive Fuels and Fuel Sysytems, Metrology, Mechanical Measurements and Instrumentation, Heat & Mass Transfer, Operations Research, Manufacturing Technology, Composites: Mechanics & Processing, Machine Design, Heat Treatment of Metals and Alloys, Mechanics of Machines, Welding Technology, Machine Dynamics and Vibrations/ Acoustics, Turbomachines, Machine Tool Technology, Thermodynamics, Analysis and Design of Machine Components, Refrigeration & Air Conditioning Systems, Jet Propulsion and Rocket Technology, Steam & Gas Turbines, Electronic Mesurement & Instrumentation, Strength of Materials, Material Science and Metallurgy

BTech Branch

BTech Automobile Engineering, BTech 1st Year Engineering, BTech Mechanical Engineering

BTech Automobile subjects

Measurement And Metrology & Instrumentation, Theory Of Machines, Mechanics Of Machines, Design Of Machine Elements, Engineering Mechanics, Thermodynamics, Strength Of Materials

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Advanced Mathematics (M2), Engineering Graphics, Basic Electronics, Engineering Physics, Environmental Studies, Mechanics Of Solids, Basic Mechanical Engineering, Engineering Mathematics (M1), Engineering Chemistry

No Reviews yet!

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Contact

Load More

Chandrakanth describes himself as Engineering Tutor. He conducts classes in BTech Tuition, Class 10 Tuition and Class 9 Tuition. Chandrakanth is located in Borabanda Parvathi Nagar, Hyderabad. Chandrakanth takes at students Home and Regular Classes- at his Home. He has 2 years of teaching experience . Chandrakanth has completed Bachelor of Technology (B.Tech.) from Matrusree engineering college in 2017. HeĀ is well versed in English, Telugu and Hindi.

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