Ashok Nagar, Bangalore, India - 560025
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Details verified of Mona A.✕
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
20
Board
CBSE
CBSE Subjects taught
Mathematics
Experience in School or College
St. Xavier's school, Delhi Army Public School, Delhi Indore Public School, Delhi
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
5
Board
CBSE
CBSE Subjects taught
Mathematics
Experience in School or College
St Xavier's school , Delhi Army Public School, Delhi Indore Public School, Indore
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
20
Board
CBSE, ICSE
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore
Taught in School or College
Yes
Teaching Experience in detail in Class 8 Tuition
Have taught in St Xavier's Delhi and Indore Public School, Indore.
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
20
Board
CBSE, ICSE
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore
Taught in School or College
Yes
Teaching Experience in detail in Class 7 Tuition
St Xavier's school Delhi Indore Public School Indore
4.7 out of 5 7 reviews
Harshitha
Class 10 Tuition
"Mona mam is an amazing teacher who would explain what you expect detailedly . She have cleared all my doubts from the beginning. "
Smitha
"Mona mam's explanation is very fluent and flexible in classes too. Very happy to take classes from her. "
Rajasekhar
"It's very nice and very happy to hire you for the course to my son. He is happy and still continuing the sessions. "
Neha
"Good experience with Ms Mona, My son enjoys the subject now and looks forward to the classes surprisingly. A very hardworking teacher. "
Reply by Mona
Am so happy that he looks forward to studying Maths. Thanks Neha
Prachi Varshney
"Very professional and highly attentive tutor she is. My daughter is continuously taking her classes since her 7th grade. We will Inshaallah will be going ahead on further with her for sure. She clears the concepts within 1-3 classes only and gels up with kid in a very good manner. We are very happy with her efforts. Thank you so much Mam. "
Reply by Mona
Thanks Prachi, your words and appreciation are indeed rewarding.God bless you
Anithababu
"A very dedicated teacher with a great passion for teaching.she concentrates more on conceptual learning and allow the kids to progress in their own pace.classes scheduled are on time and this helps the kids to be punctual.very happy and satisfied with her teaching. "
Reply by Mona
Thanks for you kind words , grateful!!
Sunayana
"Can't get a better teacher than her. She won't help you to just get the answers to the problems but also help in getting the basics right. Her understanding of child psychology is beyond compare. I am recommending her for not just for class 9 but for all classes from 7 - 10. At least have one session with her and you will know what I am talking about. She is awesome! "
Reply by Mona
Thanks for your appreciation. so very kind of you!!
Answered on 26/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7
Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7
Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7
Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7
V = (1/3)*π*r*r*h
r =10.5/2= 5.25
V= (1/3)*(22/7)*5.25*5.25*3
= 86.625 m^3
Area of the canvas = curved surface of heap = π*r*l
l = √(r*r+h*h) = √(36.5625)
=6.046 m (approx)
πrl = 3.14*5.25*6.046
= 99.668 m^2
Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7
(i)V = 1/3 * π* r*r*h
9856 = 1/3 *(22/7) *14*14*h
h= (9856*3*7)/(22*14*14)
=48 cm
(ii) slant height
l = √(r*r + h*h) = √ (196+2304)
= √2500 = 50 cm
(iii) curved surface area
π*r*l = (22/7)*14*50
=2200 cm^2
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Ashok Nagar, Chennai 
