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Answered 5 days ago Learn Tuition
Uma P.
PMP Trainer with 20 years experience
Lesson Posted on 26 Jun Learn Class 7
Jaikumar Veerwani
I specialize in teaching to students from classes 6 to 10 and 11 ,12(commerce), as well as those pursuing...
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Jaikumar Veerwani
I specialize in teaching to students from classes 6 to 10 and 11 ,12(commerce), as well as those pursuing...
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Shreya Choudhary
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Baby P.
A lawyer with 3yrs experience
Lesson Posted on 10 May Learn CBSE
Accounting for partnership: Basic concept
Deepika Agrawal
With a decade of dedicated teaching experience, I have honed my skills in fostering a dynamic and engaging...
QUESTIONS:
Answer: A partnership deed is an agreement among the partners which contains ai! the terms of the Partnership. It generally contains the details about all the aspects affecting the relationship between the partners including the objective of business, contribution of capital by each partner-ratio in which the profits and the losses will be shared by the partners and entitlement of partners to interest on capital, interest on loan etc.
Answer: As. per Partnership Act 1932 it is not necessary that a partnership agreement must be in writing but still it is always suggested that it should be in written form Because today there are very good relationship among the partners but n future if there may be any dispute regarding any issue, a written partnership agreement will help in avoiding disputes and misunderstandings among the partners.
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Answered on 07 Jun Learn General Chemistry For Maths & Physics
Rudresh Pratap Singh
Answered on 23 Jun Learn General Chemistry For Maths & Physics
Mahak Dahiya
Experienced and certified teaching Sessions of 3 years
Answered on 30/05/2021 Learn Tuition
Vaishali Mittal
Experienced Art teacher helping students learn draw and paint and be an art professional.
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Lesson Posted on 18/06/2017 Learn Science
Numerical problems on force and pressure
Soumi Roy
I am an experienced, qualified tutor with over 8 years of experience in teaching maths and Science across...
Example 1:
A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?
Given:
Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2
Thrust = Normal pressure = F = 1200 N
Pressure P = F/A 1200N10−3m21200N10−3m2
= 1.2 ×× 106 N/m2
Example 2:
The elephant weighs 20,000 N stands on one foot of area 1000 cm2. How much pressure would it exert on the ground?
Given:
Force applied by elephant F = 20,000 N, area A = 1000 cm2 = 1000/100×100m2 = 0.1 m2
The pressure is given by
Pressure P = F/A
= 20,000N/0.1m2
= 2,00,000 N/m2.
Example 3:
Calculate the pressure produced by a force of 800 N acting on an area of 2.0 m2.
Solution:
Pressure is defined as force per unit area or P = F / A
P = (800 N) / (2.0 m2
)
P = 400 N / m2
= 400 Pa
Example 4:
The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m2. Calculate the force that is exerted on the piston.
Solution
Pressure is defined as force per unit area or P = F / A
We multiply both sides of the equation by the area to solve for the force as
F = P A
F = (300 Pa) (0.5 m2
)
F = 150 (Pa) m2
= 150 (N / m2
) m2
F = 150 N
Example 5:
A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
Solution:
The pressure due to a column of fluid is calculated as the product of the height of the fluid times
the density of the fluid times the acceleration due to gravity. For water the density is d = 1000 kg /
m3
.
? P = d h g
? P = (1000 kg / m3
) (3.0 m) (9.8 m / s2
)
? P = 29400 kg m2 / m3
s2
To simplify the units we cancel one m term in the m2
term in the numerator and one m term in
the m3
term in the denominator to get
? P = 29400 kg m / s2
m2
We know that 1N = 1 kg m / s2
so we can write
? P = 29400 N / m2
= 29400 Pa
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