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Overview

I have been teaching Mathematics for last 2-3 years for GATE, JAM, X-XI, IIT JEE
Students will get brief notes on each chapter and also practice materials. Problem discussion and doubt clearance in classes will help them to be confident for the real exam.

I have co-authored a book 'Engineering Mathematics' for B.E./B.Tech. syllabus, published by Oxford University Press, New Delhi.
I have also been a member of Board of Studies for Mathematics(Hons) at R. K. Mission Residential College, Narendrapur, an autonomous college under Calcutta University for the last five years.

Languages Spoken

English

Bengali

Education

ISI, Kolkata, M.Sc.(Math) from CU 1985

Master of Engineering - Master of Technology (M.E./M.Tech.)

Address

Ballygunge, Kolkata, India - 700019

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Answers by Subodh Bhunia (1)

Answered on 22/08/2015 Learn Tuition/Class XI-XII Tuition (PUC)

What is the area of Pentagon?

The pentagon must be a regular one; otherwise it is not possible to give an expression for the area. A regular pentagon consists of 5 congruent isosceles triangle with base equal to a, the side of the pentagon and the vertical angle equal to 72 degree (at the centre of the regular pentagon). The height... ...more
The pentagon must be a regular one; otherwise it is not possible to give an expression for the area. A regular pentagon consists of 5 congruent isosceles triangle with base equal to a, the side of the pentagon and the vertical angle equal to 72 degree (at the centre of the regular pentagon). The height of each triangle is a/2 cos 36(degree). Hence area of each triangle is 1/2 base X height =a^2/4 cot 36 (degree) sq. units. Thus, the area of the polygon is 5a^2/4 X cot 36 (degree) sq. units.
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Answers by Subodh Bhunia (1)

Answered on 22/08/2015 Learn Tuition/Class XI-XII Tuition (PUC)

What is the area of Pentagon?

The pentagon must be a regular one; otherwise it is not possible to give an expression for the area. A regular pentagon consists of 5 congruent isosceles triangle with base equal to a, the side of the pentagon and the vertical angle equal to 72 degree (at the centre of the regular pentagon). The height... ...more
The pentagon must be a regular one; otherwise it is not possible to give an expression for the area. A regular pentagon consists of 5 congruent isosceles triangle with base equal to a, the side of the pentagon and the vertical angle equal to 72 degree (at the centre of the regular pentagon). The height of each triangle is a/2 cos 36(degree). Hence area of each triangle is 1/2 base X height =a^2/4 cot 36 (degree) sq. units. Thus, the area of the polygon is 5a^2/4 X cot 36 (degree) sq. units.
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Subodh Bhunia describes himself as Mathematics Coach. Subodh is located in Ballygunge, Kolkata. Subodh takes at students Home and Regular Classes- at his Home. He has 3 years of teaching experience . Subodh has completed Master of Engineering - Master of Technology (M.E./M.Tech.) from ISI, Kolkata, M.Sc.(Math) from CU in 1985. He is well versed in English and Bengali.

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