*Fraction addition :
When denominator is not same
Question:
Solve: [(2/5)+(3/7)]
Ans:
Using the rule
[(a/b)+(c/d)]
[(a×d)+(b×c)]/(b×d)
(ad+bc)/bd
By using this formula
We can solve
[(2/5)+(3/7)]
[(2×7)+(3×5)]/(5×7)
(14+15)/35
[(2/5)+(3/7)] = (29/35)
This is final answer.