Sector 61, Sahibzada Ajit Singh Nagar, India - 160062.
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English
Panjab University Pursuing
Doctor of Philosophy (Ph.D.)
Panjab University 2017
Bachelor of Commerce (B.Com.)
Panjab University 2019
Master of Commerce (M.Com.)
National Testing Agency 2019
UGC NET IN COMMERCE
Sector 61, Sahibzada Ajit Singh Nagar, India - 160062
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
CBSE Subjects taught
Accountancy
Taught in School or College
No
Teaching Experience in detail in Class 11 Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE
CBSE Subjects taught
Accountancy
Taught in School or College
No
Teaching Experience in detail in Class 12 Tuition
https://www.youtube.com/channel/UCmBrjuC7Uu2mRy5op27KOiQ
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
3
BCom Subject
Corporate Accounting, Micro & Macro Economics, Business Mathematics and Statistics, Financial Management, Financial Accounting
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BBA Tuition
3
BBA Subject
Fundamentals of Accounting, Financial Accounting, Statistics, Corporate Accounting
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BBA Tuition, BCom Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and IELTS Coaching Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
Step-by-step explanation:
Given
i )
=
/* From (1) */
=
=
=
=---(1)
ii)
=
After cancellation, we get
= ---(2)
Therefore,
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
Using pythagoras theorem,
(PR) ² = (PQ)² + (PR)²
⇒(QR)² = (13)² - (12)
=169 – 144 = 25
QR = 5 cm
tan p - cot r
= QR/PQ - QR/PQ
= 5/12 - 5/12
=0
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²
AC² = 576 + 49 = 625
AC = √625
AC = ±25
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A = BC/AC
=7/25
CosA =AB/AC
=24/25
(ii) Sin C =AB/AC
=24/25
Cos C =BC/AC
=7/25
Answered on 30/05/2018 Learn CBSE/Class 12/Commerce/Accountancy
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
CBSE Subjects taught
Accountancy
Taught in School or College
No
Teaching Experience in detail in Class 11 Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE
CBSE Subjects taught
Accountancy
Taught in School or College
No
Teaching Experience in detail in Class 12 Tuition
https://www.youtube.com/channel/UCmBrjuC7Uu2mRy5op27KOiQ
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
3
BCom Subject
Corporate Accounting, Micro & Macro Economics, Business Mathematics and Statistics, Financial Management, Financial Accounting
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BBA Tuition
3
BBA Subject
Fundamentals of Accounting, Financial Accounting, Statistics, Corporate Accounting
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
Step-by-step explanation:
Given
i )
=
/* From (1) */
=
=
=
=---(1)
ii)
=
After cancellation, we get
= ---(2)
Therefore,
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
Using pythagoras theorem,
(PR) ² = (PQ)² + (PR)²
⇒(QR)² = (13)² - (12)
=169 – 144 = 25
QR = 5 cm
tan p - cot r
= QR/PQ - QR/PQ
= 5/12 - 5/12
=0
Answered on 01/08/2019 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1
In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²
AC² = 576 + 49 = 625
AC = √625
AC = ±25
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A = BC/AC
=7/25
CosA =AB/AC
=24/25
(ii) Sin C =AB/AC
=24/25
Cos C =BC/AC
=7/25
Answered on 30/05/2018 Learn CBSE/Class 12/Commerce/Accountancy
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