Janta School Rd Rudrapur, Rudrapur, India - 263153.
Details verified of Kinri C.✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
English Basic
Srms bariely
Pursuing
Bachelor of Medicine and Bachelor of Surgery (M.B.B.S.)
Janta School Rd Rudrapur, Rudrapur, India - 263153
Phone Verified
Email Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
CBSE
CBSE Subjects taught
Biology
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 12 Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 12/07/2020 Learn CBSE/Class 1
There's nothing to worry about. It is an early age, and some children find it challenging to adapt to the new class. Wait for some time; surely, she will succeed. One thing I would suggest is that you could make things more exciting and indifferent manner so your daughter understand things and make their base more potent for the future.
Answered on 12/07/2020 Learn Tuition
Answered on 12/07/2020 Learn Tuition
Answered on 12/07/2020 Learn CBSE/Class 11
We could write it as:
∫ logxdx =∫ (logx).1dx
Now apply the integration by parts by taking first function as log x and second function as1. The formula for Integration by parts is given as
∫f(x) g(x) dx = f(x) ∫ g(x)dx - ∫ (f'(x) ∫ g(x)dx) dx.
Where f(x) is the first function and g(x) is the second function.
f(x) = (logx) And g(x)=1
After putting the values in the formula.
∫ logxdx
=∫ (logx).1dx
=x logx - ∫ 1.dx
= x logx - x + c , where c is any constant.
Hence this is our general solution.
Answered on 12/07/2020 Learn Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
CBSE
CBSE Subjects taught
Biology
Taught in School or College
No
Answered on 12/07/2020 Learn CBSE/Class 1
There's nothing to worry about. It is an early age, and some children find it challenging to adapt to the new class. Wait for some time; surely, she will succeed. One thing I would suggest is that you could make things more exciting and indifferent manner so your daughter understand things and make their base more potent for the future.
Answered on 12/07/2020 Learn Tuition
Answered on 12/07/2020 Learn Tuition
Answered on 12/07/2020 Learn CBSE/Class 11
We could write it as:
∫ logxdx =∫ (logx).1dx
Now apply the integration by parts by taking first function as log x and second function as1. The formula for Integration by parts is given as
∫f(x) g(x) dx = f(x) ∫ g(x)dx - ∫ (f'(x) ∫ g(x)dx) dx.
Where f(x) is the first function and g(x) is the second function.
f(x) = (logx) And g(x)=1
After putting the values in the formula.
∫ logxdx
=∫ (logx).1dx
=x logx - ∫ 1.dx
= x logx - x + c , where c is any constant.
Hence this is our general solution.
Answered on 12/07/2020 Learn Tuition
Want to learn from Kinri C.?
Share this Profile
Recommended Profiles
Also have a look at
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.
Alliance City One,
Rudrapur
