How do I do this in Python: for (I=0, j=n; I=0; I++, j--)?

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Michael Devine

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There may be a typo in the question. however this could be the corrected question..... for (I=0, j=n; I<n; I++, j--) >>> # for (I=0, j=n; I<n; I++, j--)>>> j=n=10 # we initialize 'n' and 'j'>>> # i<10 is the terminating condition, so we loop 'n' times. >>>...
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There may be a typo in the question. however this could be the corrected question..... for (I=0, j=n; I<n; I++, j--) >>> # for (I=0, j=n; I<n; I++, j--)>>>j=n=10 # we initialize 'n' and 'j'>>> # i<10 is the terminating condition, so we loop 'n' times.>>>for i in range(n): #in your case you are incrementing i by 1 repeatedly #and in the end i==n. j will be decrementedby 1, n times. #In Python, we simulate the 'for' loop with range() and the the Range object will have a #sequence of int objects from 0 to 9. (ie.n-1).The 'for' construct will iterate thru the #Range objectaccording to its size and stop,after which it willexecute the 'else' block. #In Python, 'else' is an independent construct that can be used when ever a condition is checked. #'else' will execute when a condition is 'False'. We initialize 'n' and 'j' outside the 'for' construct. #The range() will construct a Range object of ints from 0 to n.All we need to do is decrement j. #On successful completion of the 'for', the 'else' will execute. Here, we add 1 to 'i' to make i==n. j-=1else: i+=1 print('i= ',i,'\n','j= ',j) i= 10j= 0>>> read less
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