Ambi Road, Pune, India - 410507.
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English Basic
D Y Patil institute of engineering and technology Pursuing
BE electrical
Ambi Road, Pune, India - 410507
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics
1. Which school boards of Class 12 do you teach for?
CBSE and State
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 12 Tuition Class.
4. Do you provide a demo class?
No, I don't provide a demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 15/10/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Where, Charge, q = 5 µC = 5 × 10- 6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
Where,
= Permittivity of free space
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
Answered on 15/10/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
CASE 1
There are two charges,
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.
r = Distance of point P from charge q1
Let the electric potential (V) at point P be zero.
Potential at point P is the sum of potentials caused by charges q1 and q2 respectively.
Where,
= Permittivity of free space
For V = 0, equation (i) reduces to
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges
CASE 2
Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero,
as shown in the following figure.
For this arrangement, potential is given by,
For V = 0, equation (ii) reduces to
Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics
Answered on 15/10/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Where, Charge, q = 5 µC = 5 × 10- 6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
Where,
= Permittivity of free space
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
Answered on 15/10/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
CASE 1
There are two charges,
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.
r = Distance of point P from charge q1
Let the electric potential (V) at point P be zero.
Potential at point P is the sum of potentials caused by charges q1 and q2 respectively.
Where, = Permittivity of free space
For V = 0, equation (i) reduces to
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges
CASE 2
Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero,
as shown in the following figure.
For this arrangement, potential is given by,
For V = 0, equation (ii) reduces to
Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.
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