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Details verified of Jawed Shaikh ✕
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Education
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English
Hindi
Pune University 1997
Bachelor of Science (B.Sc.)
503, Manish Plaza, NIBM Rd, Kondhwa
N I B M, Pune, India - 411048
Landmark: Opp Brahma Majestic
ID Verified
Education Verified
Phone Verified
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Facebook Verified
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry
Teaching Experience in detail in Class 12 Tuition
I have 5+ years of experience in teaching students and helping them achieve their target and make their future successful.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
CBSE, State, ICSE
CBSE Subjects taught
Information and Comunication Technology, Science, Computer Practices, English, Hindi, Marathi, Mathematics
ICSE Subjects taught
Hindi, Computer Application, Physics, Chemistry, Biology, English Literature, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
English, Hindi, Mathematics, Marathi, Science
Teaching Experience in detail in Class 10 Tuition
Helped student in achieving their with timely help as clearing their doubt, finding the way through which the student can understand easily. We make the concept of students very clear so that he can understand the topic and score good marks
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry
Teaching Experience in detail in Class 11 Tuition
7+ years of experience in teaching students and helping them achieve their target and make their future successful
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
5
Board
State, ICSE
ICSE Subjects taught
Physics, Chemistry, Biology, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Teaching Experience in detail in Class 9 Tuition
Have 7+ years of experience in teaching and helping students to achieve their targets and make their future bright.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
5
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Science, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry
Teaching Experience in detail in Class 12 Tuition
I have 5+ years of experience in teaching students and helping them achieve their target and make their future successful.
Answered on 25/06/2019 Learn Tuition
Given: x2 +y2 +z2 = xy +yz +zx
We know that
x3 +y3 +z3 −3xyz = (x +y +z)(x2 +y2 +z2 −xy −yz −zx).
Substituting the value of x2 +y2 +z2 in above equation, we get
x3 +y3 +z3 −3xyz = (x +y +z)( xy +yz +zx −xy −yz −zx)
x3 +y3 +z3 −3xyz = (x +y +z) (0) …… ………………… ( xy +yz +zx −xy −yz –zx ) = 0
x3 +y3 +z3 −3xyz = 0 …………………………………………………….(x +y +z) (0) = 0
x3 +y3 +z3 = 3xyz
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry
Teaching Experience in detail in Class 12 Tuition
I have 5+ years of experience in teaching students and helping them achieve their target and make their future successful.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
CBSE, State, ICSE
CBSE Subjects taught
Information and Comunication Technology, Science, Computer Practices, English, Hindi, Marathi, Mathematics
ICSE Subjects taught
Hindi, Computer Application, Physics, Chemistry, Biology, English Literature, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
English, Hindi, Mathematics, Marathi, Science
Teaching Experience in detail in Class 10 Tuition
Helped student in achieving their with timely help as clearing their doubt, finding the way through which the student can understand easily. We make the concept of students very clear so that he can understand the topic and score good marks
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry
Teaching Experience in detail in Class 11 Tuition
7+ years of experience in teaching students and helping them achieve their target and make their future successful
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
5
Board
State, ICSE
ICSE Subjects taught
Physics, Chemistry, Biology, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Teaching Experience in detail in Class 9 Tuition
Have 7+ years of experience in teaching and helping students to achieve their targets and make their future bright.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
5
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Science, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Answered on 25/06/2019 Learn Tuition
Given: x2 +y2 +z2 = xy +yz +zx
We know that
x3 +y3 +z3 −3xyz = (x +y +z)(x2 +y2 +z2 −xy −yz −zx).
Substituting the value of x2 +y2 +z2 in above equation, we get
x3 +y3 +z3 −3xyz = (x +y +z)( xy +yz +zx −xy −yz −zx)
x3 +y3 +z3 −3xyz = (x +y +z) (0) …… ………………… ( xy +yz +zx −xy −yz –zx ) = 0
x3 +y3 +z3 −3xyz = 0 …………………………………………………….(x +y +z) (0) = 0
x3 +y3 +z3 = 3xyz
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