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Overview

I can teach every topic of maths very easily and make it stronger for the students.i am teaching more than 15 years as maths teacher

Languages Spoken

Hindi Proficient

English Basic

Education

Delhi university 2007

Bachelor of Science (B.Sc.)

Sikkim manipal university 2009

Master of Business Administration (M.B.A.)

monard university 2013

Master of Science (M.Sc.)

Address

Sector 110, Noida, India - 201304

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Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

14

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 12 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 14 years.

Answers by Manoj Kumar (2)

Answered on 24/06/2019 Learn Tuition

As we know the formula, +-3xyz= (x + y+ z)( x² +y² +z² - xy - yz - zx)........1 Given now substitue the value in (1) (x+Y+Z)(0)=0 so +=3xyz this is the given solution ...more

As we know the formula,

+-3xyz=

(x + y+ z)( x² +y² +z² - xy - yz - zx)........1

Given

  now substitue the value in (1)

(x+Y+Z)(0)=0 so

 +=3xyz  this is the given solution

 

Answers 278 Comments
Dislike Bookmark

Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

14

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

No Reviews yet!

Answers by Manoj Kumar (2)

Answered on 24/06/2019 Learn Tuition

As we know the formula, +-3xyz= (x + y+ z)( x² +y² +z² - xy - yz - zx)........1 Given now substitue the value in (1) (x+Y+Z)(0)=0 so +=3xyz this is the given solution ...more

As we know the formula,

+-3xyz=

(x + y+ z)( x² +y² +z² - xy - yz - zx)........1

Given

  now substitue the value in (1)

(x+Y+Z)(0)=0 so

 +=3xyz  this is the given solution

 

Answers 278 Comments
Dislike Bookmark

Manoj Kumar conducts classes in Class 12 Tuition. Manoj is located in Sector 110, Noida. Manoj takes at students Home. He has 14 years of teaching experience . Manoj has completed Bachelor of Science (B.Sc.) from Delhi university in 2007, Master of Business Administration (M.B.A.) from Sikkim manipal university in 2009 and Master of Science (M.Sc.) from monard university in 2013. HeĀ is well versed in English and Hindi.

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