/> Sector 110, Noida, India - 201304.
Details verified of Manoj Kumar✕
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Education
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Hindi Proficient
English Basic
Delhi university 2007
Bachelor of Science (B.Sc.)
Sikkim manipal university 2009
Master of Business Administration (M.B.A.)
monard university 2013
Master of Science (M.Sc.)
Sector 110, Noida, India - 201304
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
14
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
Yes
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class 12 Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 14 years.
Answered on 24/06/2019 Learn Tuition
As we know the formula,
+
-3xyz=
(x + y+ z)( x² +y² +z² - xy - yz - zx)........1
Given
now substitue the value in (1)
(x+Y+Z)(0)=0 so
+
=3xyz this is the given solution
Answered on 05/05/2019 Learn Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
14
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
Yes
Answered on 24/06/2019 Learn Tuition
As we know the formula,
+
-3xyz=
(x + y+ z)( x² +y² +z² - xy - yz - zx)........1
Given
now substitue the value in (1)
(x+Y+Z)(0)=0 so
+
=3xyz this is the given solution
Answered on 05/05/2019 Learn Tuition
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Sector 110, Noida 
