Find the best tutors and institutes for Class 7 Tuition
Search in
Find the area of each of the following parallelograms:
Area of parallelogram = Base × Height
(a) Height= 4 cm
Base = 7 cm
Area of parallelogram = 7 × 4 = 28 cm2
(b) Height= 3 cm
Base = 5 cm
Area of parallelogram = 5 × 3 = 15 cm2
(c) Height= 3.5 cm
Base = 2.5 cm
Area of parallelogram = 2.5 × 3.5 = 8.75 cm2
(d) Height= 4.8 cm
Base = 5 cm
Area of parallelogram = 5 × 4.8 = 24 cm2
(e) Height= 4.4 cm
Base = 2 cm
Area of parallelogram = 2 × 4.4 = 8.8 cm2
Find the area of each of the following triangles:
(a) Base = 4 cm, height= 3 cm
Area 
= 6 cm2
(b) Base = 5 cm, height= 3.2 cm
Area 
= 8 cm2
(c) Base = 4 cm, height= 3 cm
Area = 6 cm2
(d)Base = 3 cm, height= 2 cm
Area =
= 3 cm2
Find the missing values:
| So No | Base | Height | Area of parallelogram |
| a. | 20 cm | - | 246 cm2 |
| b. | - | 15 cm | 154.5 cm2 |
| c. | - | 8.4 cm | 48.72 cm2 |
| d. | 15.6 cm | - | 16.38 cm2 |
Area of parallelogram = Base × Height
(a) b = 20 cm
h = ?
Area = 246 cm2
20 × h = 246
Therefore, the height of such parallelogram is 12.3 cm.
(b) b = ?
h = 15 cm
Area = 154.5 cm2
b × 15 = 154.5
b = 10.3 cm
Therefore, the base of such parallelogram is 10.3 cm.
(c) b = ?
h = 8.4 cm
Area = 48.72 cm2
b × 8.4 = 48.72
Therefore, the base of such parallelogram is 5.8 cm.
(d) b = 15.6 cm
h = ?
Area = 16.38 cm2
15.6 × h = 16.38
Therefore, the height of such parallelogram is 1.05 cm.
Find the missing values:
| Base | Height | Area of triangle |
| 15 cm | _______ | 87 cm2 |
| _______ | 31.4 mm | 1256 mm2 |
| 22 cm | _______ | 170.5 cm2 |
(a) b = 15 cm
h = ?
Area =
Therefore, the height of such triangle is 11.6 cm.
(b) b = ?
h = 31.4 mm
Area =
Therefore, the base of such triangle is 80 mm.
(c) b = 22 cm
h = ?
Area =
Therefore, the height of such triangle is 15.5 cm.
PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) the area of the parallelogram PQRS
(b) QN, if PS = 8 cm
(a) Area of parallelogram = Base × Height = SR × QM
= 7.6 × 12 = 91.2 cm2
(b) Area of parallelogram = Base × Height = PS × QN = 91.2 cm2
QN × 8 = 91.2
​​​​​​​​​
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (see the given figure). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL.
Area of parallelogram = Base × Height = AB × DL
1470 = 35 × DL
Also, 1470 = AD × BM
1470 = 49 × BM
ΔABC is right angled at A (see the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.
Area =
= 30 cm2
​​​​​​​​​​​​
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (see the given figure). The height AD from A to BC, is 6 cm. Find the area of ΔABC. What will be the height from C to AB i.e., CE?
How helpful was it?
How can we Improve it?
Please tell us how it changed your life *
Please enter your feedback
UrbanPro.com helps you to connect with the best Class 7 Tuition in India. Post Your Requirement today and get connected.
Find best tutors for Class 7 Tuition Classes by posting a requirement.
Get started now, by booking a Free Demo Class
