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Find the principal values of the following:
(i) (ii) (iii)
(iv) (v) (vi)
(vii) (viii) (ix)
(x)
(i) Let sin-1 (-1/2) = y . then siny=-1/2 = -sin(Π/6) = sin (-Π/6)
Implies the range of the principal value branch of sin-1 is [-Π/2,Π/2]
and sin (-Π/6) = -1/2 implies the principal value of sin-1(-1/2)= -Π/6
(ii)
Let cos-1(√3/2) = y . then cosy=√3/2 = cos(Π/6)
Implies the range of the principal value branch of cos-1 is [0,Π]
and cos(Π/6) = √3/2 implies the principal value of cos-1(√3/2)= Π/6
(iii)
Let cosec-1(2) = y . then cosecy=2 = cosec(Π/6)
Implies the range of the principal value branch of cosec-1 is [-Π/2,Π/2]-{0}
and cosec(Π/6) = 2 implies the principal value of cosec-1(2)= Π/6
(iv)
Let tan-1(-√3) = y . then tany=-√3 = -tan(Π/3) =tan(-Π/3)
Implies the range of the principal value branch of tan-1 is (-Π/2,Π/2)
and tan(-Π/3) = -√3 implies the principal value of tan-1(-√3)= -Π/3
(v)
Let cos-1(-1/2) = y . then cosy=-1/2 = -cos(Π/3) =cos(Π-Π/3) =cos(2Π/3)
Implies the range of the principal value branch of cos-1 is [0,Π]
and cos(2Π/3) = -1/2 implies the principal value of cos-1(-1/2)= Π/6
(vi)
Let tan-1(-1) = y . then tany=-1 = -tan(Π/4) =tan(-Π/4)
Implies the range of the principal value branch of tan-1 is (-Π/2,Π/2)
and tan(-Π/4) = -1 implies the principal value of tan-1(-1)= -Π/4
(vii)
Let sec-1(2/√3) = y . then secy=2/√3 = sec(Π/6)
Implies the range of the principal value branch of cosec-1 is [-0,Π]-{Π/2}
and sec(Π/6) = 2/√3 implies the principal value of sec-1(2/√3)= Π/6
(viii)
Let cot-1(√3) = y . then coty=√3 = cot(Π/6)
Implies the range of the principal value branch of cot-1 is (0,Π)
and cot(Π/6) = √3 implies the principal value of cot-1(√3)= Π/6
(ix)
Let cos-1(-1/√2) = y . then cosy=-1/√2 = -cos(Π/4) =cos(Π-Π/4) =cos(3Π/4)
Implies the range of the principal value branch of cos-1 is [0,Π]
and cos(3Π/4) = -1/√2 implies the principal value of cos-1(-1/√2)= 3Π/4
(x)
Let cosec-1(-√2) = y . then cosecy=-√2 = -cosec(Π/4) =cosec(-Π/4)
Implies the range of the principal value branch of cosec-1 is [-Π/2,Π/2]-{0}
and cosec(-Π/4) = -√2 implies the principal value of cosec-1(-√2)= -Π/4
Find the values of the following:
1.
2.
is equal A) B) C) D)
Let tan. Then tan x
The range of the principle value branch of is
Let Then, sec y=
We know that the range of the principal value branch of is
Hence =
Hence option B
If then, A) B)
C) 0 < y < π D)
It is given that sin−1x = y.
We know that the range of the principal value branch of sin−1 is
Therefore,.
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