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Differentiate w.r.t. x the function
Differentiate w.r.t. x the function
Using chain rule, we obtain
Differentiate w.r.t. x the function
Taking logarithm on both the sides, we obtain
Differentiating both sides with respect to x, we obtain
Differentiate w.r.t. x the function
Using chain rule, we obtain
Differentiate w.r.t. x the function
Therefore, equation (1) becomes
Differentiate w.r.t. x the function
Taking logarithm on both the sides, we obtain
Differentiating both sides with respect to x, we obtain
Differentiate w.r.t. x the function , for some constant a and b.
By using chain rule, we obtain
Differentiate w.r.t. x the function
Taking logarithm on both the sides, we obtain
Differentiating both sides with respect to x, we obtain
Differentiate w.r.t. x the function
, for some fixed and
Differentiating both sides with respect to x, we obtain
Differentiating both sides with respect to x, we obtain
s = aa
Since a is constant, aa is also a constant.
∴
From (1), (2), (3), (4), and (5), we obtain
Differentiate w.r.t. x the function , for
Differentiating both sides with respect to x, we obtain
Differentiating with respect to x, we obtain
Also,
Differentiating both sides with respect to x, we obtain
Substituting the expressions of in equation (1), we obtain
Find, if
Find, if
If, for, −1 < x <1, prove that
It is given that,
Differentiating both sides with respect to x, we obtain
Hence, proved.
If, for some prove that
is a constant independent of a and b.
It is given that,
Differentiating both sides with respect to x, we obtain
Hence, proved.
If with prove that
Then, equation (1) reduces to
⇒sin(a+y−y)
Hence, proved.
If and, find
If, show that exists for all real x, and find it.
It is known that,
Therefore, when x ≥ 0,
In this case, and hence,
When x < 0,
In this case, and hence,
Thus, for, exists for all real x and is given by,
Using mathematical induction prove that for all positive integers n.
For n = 1,
∴P(n) is true for n = 1
Let P(k) is true for some positive integer k.
That is,
It has to be proved that P(k + 1) is also true.
Thus, P(k + 1) is true whenever P (k) is true.
Therefore, by the principle of mathematical induction, the statement P(n) is true for every positive integer n.
Hence, proved.
Using the fact that sin (A + B) = sin A cos B + cos A sin B and the differentiation, obtain the sum formula for cosines.
Differentiating both sides with respect to x, we obtain
Does there exist a function which is continuos everywhere but not differentiable at exactly two points? Justify your answer ?
It can be seen from the above graph that, the given function is continuos everywhere but not differentiable at exactly two points which are 0 and 1.
If, prove that
Thus,
If, show that
It is given that,
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