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Calculate the ‘spin only’ magnetic moment of M2+(aq) ion (Z = 27).
The atomic number Z =27 corresponds to Cobalt and Cobalt has 3 unpaired electrons(n=3).
The spin magnetic moment mu(S) =sqrt [n(n+2)]
=sqrt [3(3+2)]
=sqrt(15)
=3.87 BM (approx)
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