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Find the derivative of x2 – 2 at x = 10.
Let f(x) = x2 – 2. Accordingly,
Thus, the derivative of x2 – 2 at x = 10 is 20.
Find the derivative of x at x = 1.
Let f(x) = x. Accordingly,
Thus, the derivative of x at x = 1 is 1.
Find the derivative of 99x at x = 100.
Let f(x) = 99x. Accordingly,
Thus, the derivative of 99x at x = 100 is 99.
Find the derivative of the following functions from first principle.
(i) x3 – 27 (ii) (x – 1) (x – 2)
(ii) (iv)
(i) Let f(x) = x3 – 27. Accordingly, from the first principle,
(ii) Let f(x) = (x – 1) (x – 2). Accordingly, from the first principle,
(iii) Let. Accordingly, from the first principle,
(iv) Let. Accordingly, from the first principle,
For the function
Prove that
The given function is
Thus,
Find the derivative offor some fixed real number a.
Let
For some constants a and b, find the derivative of
(i) (x – a) (x – b) (ii) (ax2 + b)2 (iii)
(i) Let f (x) = (x – a) (x – b)
(ii) Let
(iii)
By quotient rule,
Find the derivative offor some constant a.
By quotient rule,
Find the derivative of
(i) (ii) (5x3 + 3x – 1) (x – 1)
(iii) x–3 (5 + 3x) (iv) x5 (3 – 6x–9)
(v) x–4 (3 – 4x–5) (vi)
(i) Let
(ii) Let f (x) = (5x3 + 3x – 1) (x – 1)
By Leibnitz product rule,
(iii) Let f (x) = x– 3 (5 + 3x)
By Leibnitz product rule,
(iv) Let f (x) = x5 (3 – 6x–9)
By Leibnitz product rule,
(v) Let f (x) = x–4 (3 – 4x–5)
By Leibnitz product rule,
(vi) Let f (x) =
By quotient rule,
Find the derivative of cos x from first principle.
Let f (x) = cos x. Accordingly, from the first principle,
Find the derivative of the following functions:
(i) sin x cos x (ii) sec x (iii) 5 sec x + 4 cos x
(iv) cosec x (v) 3cot x + 5cosec x
(vi) 5sin x – 6cos x + 7 (vii) 2tan x – 7sec x
(i) Let f (x) = sin x cos x. Accordingly, from the first principle,
(ii) Let f (x) = sec x. Accordingly, from the first principle,
(iii) Let f (x) = 5 sec x + 4 cos x. Accordingly, from the first principle,
(iv) Let f (x) = cosec x. Accordingly, from the first principle,
(v) Let f (x) = 3cot x + 5cosec x. Accordingly, from the first principle,
From (1), (2), and (3), we obtain
(vi) Let f (x) = 5sin x – 6cos x + 7. Accordingly, from the first principle,
(vii) Let f (x) = 2 tan x – 7 sec x. Accordingly, from the first principle,
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