NCERT Solutions for Class 10 Maths, Chapter 13 - Surface Areas and Volumes

In Class 9, you became familiar with solid structures such as cone, cylinder, cuboid, and sphere etc. You also learned how to find the volume and surface area of these structures. In this chapter, you will learn to find surface areas of the combination of solids such as cone, cylinder, sphere, hemisphere and cuboid, the volume of the combination of solids such as cone, cylinder, sphere, hemisphere and cuboid, conversion of solid from one state to another, and frustum of a cone.

Let us take a look at the topics and sub-topics of Class 10 Maths, Chapter 13 Solutions-

13.1 Introduction

13.2 Surface area of a combination of solids

13.3 Volume of a combination of solids

13.4 Conversion of solid from one state to another

13.5 Frustum of a cone

13.6 Summary

In Surface Area and Volume Class 10, we study-

How to find surface areas of the combination of solids such as cone, cylinder, sphere, hemisphere and cuboid; the volume of the combination of solids such as cone, cylinder, sphere, hemisphere and cuboid; and conversion of solid from one state to another. Also, we learn to find the frustum of a cone when a right circular cone is sliced through a parallel plane to its base, and when the smaller conical portion is removed, the remaining solid is called, ‘frustum of a cone’.

Download UrbanPro’s NCERT Solutions for Class 10 Maths Chapter 13 PDF for detailed information.