UrbanPro
true
Kousalya S. Class 11 Tuition trainer in Mumbai/>

Kousalya S.

Powai, Mumbai, India - 400076.

Contact
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Kousalya S.

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

18 years of experience in teaching physics for class XI & XII CBSE and ISC including board corrections and conducting board practicals. Have taught in several leading schools and also taken home tuition for the last decade.

MY WAY OF TEACHING ---

1. Will be able to teach as per NEED OF THE CHILD INDIVIDUALLY
2. CONCEPTUAL AND PROBLEMS are dealt in detail
3. REGULAR TESTS after completion of each chapter
4. students scoring below 20 % were brought to the level of 70 to 80%
5. SPECIAL ATTENTION will be given for weak areas
6. FIRST SAMPLE TUITION CLASS FREE
7. COACHING assured for higher marks in 2019 board exams

Languages Spoken

Tamil Mother Tongue (Native)

Hindi Proficient

English Proficient

Education

Madurai Kamaraj University 1992

Master of Science (M.Sc.)

Address

Powai, Mumbai, India - 400076

Verified Info

Phone Verified

Email Verified

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

18

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

18

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE, ISC/ICSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 18 years.

Answers by Kousalya S. (2)

Answered on 14/10/2018 Learn CBSE/Class 11/Science/Physics

Yes. Theoretically possible. But the impact it will have on the internal organs of the passengers and the car itself will be far more than the acident it would have caused by a not so instat stop. imagine at 80 KMph when an instant stop occurs, all seat belts will snap. needs new design, the car itself... ...more

Yes. Theoretically possible. But the impact it will have on the internal organs of the passengers and the car itself will be far more than the acident it would have caused by a not so instat stop. imagine at 80 KMph when an instant stop occurs, all seat belts will snap. needs new design, the car itself will roll over and cause more damage

 

Answers 2 Comments
Dislike Bookmark

Answered on 06/10/2018 Learn CBSE/Class 11/Science/Physics

The forces acting on the cycle and cyclists are weight of the cycle and cyclist together = mg vertically downwards and the reaction by the ground on the cycle tyre at an angle θ to the vertical. Resolve this reaction R in Vertical component - Rcosθ and Horizontal component Rsinθ. Equating... ...more

The forces acting on the cycle and cyclists are weight of the cycle and cyclist together = mg vertically downwards

and the reaction by the ground on the cycle tyre at an angle θ to the vertical. Resolve this reaction R in Vertical component - Rcosθ and Horizontal component Rsinθ. Equating the vertical forces Rcosθ = mg and the horizontal force is nothing but the centripetal force Rsinθ = mv2/r; 

Divide second equation by first Rsinθ/Rcosθ = v2/rg; tanθ = v2/rg or θ = tan-1(v2/rg)

Please remember we have ignored the frictional force between the tyre and the ground here

Answers 1 Comments
Dislike Bookmark

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

18

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

18

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

No Reviews yet!

Answers by Kousalya S. (2)

Answered on 14/10/2018 Learn CBSE/Class 11/Science/Physics

Yes. Theoretically possible. But the impact it will have on the internal organs of the passengers and the car itself will be far more than the acident it would have caused by a not so instat stop. imagine at 80 KMph when an instant stop occurs, all seat belts will snap. needs new design, the car itself... ...more

Yes. Theoretically possible. But the impact it will have on the internal organs of the passengers and the car itself will be far more than the acident it would have caused by a not so instat stop. imagine at 80 KMph when an instant stop occurs, all seat belts will snap. needs new design, the car itself will roll over and cause more damage

 

Answers 2 Comments
Dislike Bookmark

Answered on 06/10/2018 Learn CBSE/Class 11/Science/Physics

The forces acting on the cycle and cyclists are weight of the cycle and cyclist together = mg vertically downwards and the reaction by the ground on the cycle tyre at an angle θ to the vertical. Resolve this reaction R in Vertical component - Rcosθ and Horizontal component Rsinθ. Equating... ...more

The forces acting on the cycle and cyclists are weight of the cycle and cyclist together = mg vertically downwards

and the reaction by the ground on the cycle tyre at an angle θ to the vertical. Resolve this reaction R in Vertical component - Rcosθ and Horizontal component Rsinθ. Equating the vertical forces Rcosθ = mg and the horizontal force is nothing but the centripetal force Rsinθ = mv2/r; 

Divide second equation by first Rsinθ/Rcosθ = v2/rg; tanθ = v2/rg or θ = tan-1(v2/rg)

Please remember we have ignored the frictional force between the tyre and the ground here

Answers 1 Comments
Dislike Bookmark

Kousalya S. conducts classes in Class 11 Tuition and Class 12 Tuition. Kousalya is located in Powai, Mumbai. Kousalya takes Regular Classes- at her Home. She has 18 years of teaching experience . Kousalya has completed Master of Science (M.Sc.) from Madurai Kamaraj University in 1992. She is well versed in Hindi, English and Tamil.

X
X

Post your Learning Need

Let us shortlist and give the best tutors and institutes.

or

Send Enquiry to Kousalya S.

Let Kousalya S. know you are interested in their class

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more