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Overview

My name is Surbhi Deshwal . I am a teacher of Science but i teach all subjects to class 3-8. I am giving tution at my home which is in modipuran A2Z. I have 7 years of teaching experience. New batches will be started from 1 June. ✌️✌️

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

UPTU 2015

Bachelor of Technology (B.Tech.)

CCSU 2020

Bachelor of Education (B.Ed.)

CBSE 2021

TEACHER ELEGIBILITY TEST CERTIFICATE ( Prinmary and Secondary)

Address

Modipuram, Meerut, India - 250001

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Teaches

Class I-V Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

7

Fees

₹ 200.0 per hour

Board

ICSE, CBSE

CBSE Subjects taught

Sanskrit, Computers, Science, Social Science, Hindi, Mathematics, EVS, English

ICSE Subjects taught

EVS, Computer science, Mathematics, Hindi, Science, Social Studies, English, Sanskrit

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

ICSE and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class I-V Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 7 years.

Answers by Surbhi D. (1)

Answered on 19/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

Let The present age of P = 5x The present age of Q = 7x After 6 years The age of P = 5x + 6 According to question The difference between Q and P age = 7x - (5x + 6) = 2 7x - 5x - 6 = 2 ... ...more
Let The present age of P = 5x The present age of Q = 7x After 6 years The age of P = 5x + 6 According to question The difference between Q and P age = 7x - (5x + 6) = 2 7x - 5x - 6 = 2 2x = 2 + 6 2x = 8 x = 4 Therefore The present age of P = 5 X 4= 20 years The present age of Q = 7 X 4= 28 years Total present age of P and Q = 48 years
Answers 353 Comments
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Teaches

Class I-V Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

7

Fees

₹ 200.0 per hour

Board

ICSE, CBSE

CBSE Subjects taught

Sanskrit, Computers, Science, Social Science, Hindi, Mathematics, EVS, English

ICSE Subjects taught

EVS, Computer science, Mathematics, Hindi, Science, Social Studies, English, Sanskrit

Taught in School or College

Yes

No Reviews yet!

Answers by Surbhi D. (1)

Answered on 19/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

Let The present age of P = 5x The present age of Q = 7x After 6 years The age of P = 5x + 6 According to question The difference between Q and P age = 7x - (5x + 6) = 2 7x - 5x - 6 = 2 ... ...more
Let The present age of P = 5x The present age of Q = 7x After 6 years The age of P = 5x + 6 According to question The difference between Q and P age = 7x - (5x + 6) = 2 7x - 5x - 6 = 2 2x = 2 + 6 2x = 8 x = 4 Therefore The present age of P = 5 X 4= 20 years The present age of Q = 7 X 4= 28 years Total present age of P and Q = 48 years
Answers 353 Comments
Dislike Bookmark

Surbhi D. describes herself as Science ,Mathematics and Computer Teacher for last 7 Years. She conducts classes in Class I-V Tuition. Surbhi is located in Modipuram, Meerut. Surbhi takes Regular Classes- at her Home and Online Classes- via online medium. She has 7 years of teaching experience . Surbhi has completed Bachelor of Technology (B.Tech.) from UPTU in 2015 and Bachelor of Education (B.Ed.) from CCSU in 2020. She is well versed in English and Hindi.

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