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Post a LessonAnswered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Take Class 12 Tuition from the Best Tutors
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Given; f(x) = (x + 1)3 (x – 3)3 ⇒ f'(x) = (x + 1)3 3(x – 3)2 + (x – 3)33(x + 1)2 = 3(x + 1)2(x – 3)2(x + 1 + x – 3) = 3(x + 1)2(x – 3)2(2x – 2) = 6(x +1)2 (x – 3)2 (x -1) ⇒ 6(x +1)2 (x – 3)2 (x – 1) = 0 ⇒ x = -1, 1, 3 The intervals are (-∞, -1), (-1, 1), (1, 3), (3, ∞) f'(-2) = (-2 – 1) < 0 ∴ Strictly decreasing in (-∞, -1) f'(0) = (0 – 1) < 0 ∴ Strictly decreasing in (-1, 1) f'(2) = (2 – 1) > 0 ∴ Strictly increasing in (1, 3) f'(4) = (4 – 1) > 0 ∴ Strictly increasing in (3, ∞)
read lessAnswered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Take Class 12 Tuition from the Best Tutors
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
Answered on 06 Apr Learn Applications of Derivatives
Sadika
To find the marginal revenue (MR) when 17 units are produced, we first need to find the derivative of the revenue function R(x)R(x) with respect to xx. The marginal revenue is the rate of change of total revenue with respect to the number of units produced.
Given that R(x)=13x2+26x+15R(x)=13x2+26x+15, we find the derivative R′(x)R′(x) and evaluate it at x=17x=17.
First, let's find R′(x)R′(x): R′(x)=dRdx=ddx(13x2+26x+15)R′(x)=dxdR=dxd(13x2+26x+15)
Using the power rule of differentiation: R′(x)=26x+26R′(x)=26x+26
Now, we evaluate R′(x)R′(x) at x=17x=17: R′(17)=26(17)+26R′(17)=26(17)+26 R′(17)=442+26R′(17)=442+26 R′(17)=468R′(17)=468
So, the marginal revenue when 17 units are produced is 468468 Rs/unit.
Answered on 27/01/2022 Learn Applications of Derivatives
Pugazhendhi V
IT Technical Executive with 4 years of experience
Solution:
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Answered on 30/04/2020 Learn Applications of Derivatives
Dr Shweta K.
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