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Unit 9-Electronic Devices Lessons
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Post a LessonAnswered on 06 Apr Learn CBSE/Class 12/Science/Physics/Unit 9-Electronic Devices
Sadika
In a p-n junction, the width of the depletion layer changes depending on whether it is forward biased or reverse biased:
(i) Forward Biased:
(ii) Reverse Biased:
In summary, forward biasing reduces the width of the depletion layer, facilitating current flow, while reverse biasing increases the width of the depletion layer, limiting current flow.
Answered on 07 Apr Learn CBSE/Class 12/Science/Physics/Unit 9-Electronic Devices
Nazia Khanum
Intrinsic semiconductors are materials like pure silicon or germanium, which have a balance of electrons and holes due to thermal excitation. At absolute zero temperature (0 Kelvin), these materials would behave like perfect insulators because there wouldn't be any thermally generated charge carriers (electrons and holes) available for conduction.
However, as you increase the temperature, thermal energy provides electrons with enough energy to jump from the valence band to the conduction band, creating electron-hole pairs. This increases the conductivity of the semiconductor. The temperature at which the intrinsic semiconductor behaves like a perfect insulator depends on the energy gap between the valence band and the conduction band. This energy gap is known as the bandgap (Eg).
The relationship between the conductivity (σ) and temperature (T) in intrinsic semiconductors is given by the exponential equation known as the intrinsic carrier concentration equation:
ni=AT3/2e−Eg2kTni=AT3/2e−2kTEg
Where:
As the temperature increases, the exponential term in the equation decreases. Therefore, at higher temperatures, the intrinsic carrier concentration increases, and the material becomes more conductive. Conversely, at lower temperatures, the intrinsic carrier concentration decreases, and the material behaves more like an insulator.
However, it's important to note that "perfect insulator" is a theoretical concept. In practical terms, even at low temperatures, there can still be some level of conductivity due to impurities or defects in the material.
Answered on 07 Apr Learn CBSE/Class 12/Science/Physics/Unit 9-Electronic Devices
Nazia Khanum
A p-n junction diode can be used as a half-wave rectifier to convert an alternating current (AC) signal into a pulsating direct current (DC) signal. In a half-wave rectifier circuit, the diode conducts current only when it is forward-biased (i.e., when the p-type material is connected to the positive terminal of the AC source and the n-type material is connected to the negative terminal of the AC source).
Here's how the circuit works:
AC Input Source: The AC input source provides the alternating current signal that needs to be rectified.
P-N Junction Diode (D): The p-n junction diode is connected in series with the load resistor (RL). The diode conducts current only when it is forward-biased.
Load Resistor (RL): The load resistor is connected in series with the diode to provide a path for the current to flow through when the diode is forward-biased.
Here's the circuit diagram:
AC Input Load Source Resistor | | | | | | V V ___ | ___ | | | | | |______| --| |---|---| |------|>-- |___| | |___| D | ___ ___ | | | | | | --| |------| |-------|-- |___| |___| | GND
Explanation:
During the positive half-cycle of the AC input signal, the p-terminal of the diode becomes positive and the n-terminal becomes negative. This forward-biases the diode, allowing current to flow through it and the load resistor, completing the circuit. As a result, current flows through the load resistor and we get an output voltage across the load resistor.
During the negative half-cycle of the AC input signal, the p-terminal of the diode becomes negative and the n-terminal becomes positive. This reverse-biases the diode, blocking current flow through it, and thus no current flows through the load resistor. As a result, there is no output voltage across the load resistor during the negative half-cycle.
So, at the output, we get a pulsating DC signal which is the positive half-cycles of the AC input signal. This is why it's called a half-wave rectifier, as it rectifies only one half of the input AC waveform.
Answered on 07 Apr Learn CBSE/Class 12/Science/Physics/Unit 9-Electronic Devices
Nazia Khanum
A photodiode is a semiconductor device that converts light into an electrical current. It is commonly operated under reverse bias for several reasons:
Increased Depletion Region: When a photodiode is reverse biased, the width of the depletion region increases. This widening of the depletion region allows for more efficient absorption of photons, enhancing the device's sensitivity to light.
Reduced Dark Current: Reverse biasing reduces the dark current of the photodiode. Dark current refers to the current that flows through the photodiode even when there is no light present. By operating under reverse bias, dark current is minimized, leading to better signal-to-noise ratio and improved performance in low-light conditions.
Faster Response Time: Reverse biasing can improve the response time of the photodiode. It reduces the capacitance of the photodiode, which in turn decreases the time it takes for the photodiode to respond to changes in incident light intensity.
Lower Noise: Reverse biasing helps in reducing the noise generated by the photodiode. This noise reduction contributes to better overall performance, especially in applications where precise measurements are required.
Linear Response: Reverse biasing allows for a more linear response of the photodiode to changes in incident light intensity over a wider range, making it suitable for applications requiring accurate light detection and measurement.
Overall, operating a photodiode under reverse bias enhances its performance in terms of sensitivity, response time, noise reduction, and linearity, making it suitable for various light detection applications such as in optical communication, light sensing, and imaging.
Asked on 06/12/2021 Learn CBSE/Class 12/Science/Physics/Unit 9-Electronic Devices
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