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Motion in a Straight Line

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Motion in a Straight Line Questions

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Answered on 15/09/2018 Learn Motion in a Straight Line +1 CBSE/Class 11/Science/Physics

Mandeep Kaur

Distance travelled will be the area under the speed time curve. (a) Distance travelled is: 2 x 1/2 (5x12) = 60m (b) Slope of upward increasing curve: 12/5 and of decreasing curve it is: -12/5 This gives the rate of change of speed with time. Thus equation of line, speed at 2nd second... read more
Distance travelled will be the area under the speed time curve.
 
(a) Distance travelled is: 2 x 1/2 (5x12) = 60m
 
(b) Slope of upward increasing curve: 12/5 and of decreasing curve it is: -12/5
      This gives the rate of change of speed with time.
      Thus equation of line, speed at 2nd second will be:12/5*2 = 4.8 m/s
      Speed at 6th second: 12 - 12/5*1 = 48/5 = 9.6 m/s....  (because rate of change is negative
      and from 12 to 0)
      Thus total distance travelled = 1/2(12-4.8)(5-2) + 1/2(12-9.3)(6-5) = 12.15 m
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Answered on 14/09/2018 Learn Motion in a Straight Line +1 CBSE/Class 11/Science/Physics

Abhishek Aman

Tutor

Both are in opposite direction,so consider one velocity in negative direction. Velocity of jet w.r.t. ground Vjg= 500 km/h …...(Upward) Velocity of products relative to jet VPJ = 1500 km/h ... read more

Both are in opposite direction,so consider one velocity in negative direction.

    Velocity of jet w.r.t. ground Vjg= 500 km/h                                                                …...(Upward)

        Velocity of products relative to jet VPJ = 1500 km/h                                                …(downward)

Hence, velocity of  products relative to ground = -1500+500

                                                                                    =  -1000 km/h

Here – ve sign means downward .

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Answered on 15/09/2018 Learn Motion in a Straight Line +1 CBSE/Class 11/Science/Physics

Vijay Giri

Tutor

Distance Vs time graph is parabolic graph in case of n sec but it's straight line if we draw graph for distance Vs nth second time graph passing through origin as u=0 and acceleration constant
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