Learn Ordering of integers with Free Lessons & Tips

Let's compare each pair of integers:

(i) -5 and -7: -5 is greater than -7 because it is closer to 0 on the number line.

(ii) -7 and 5: 5 is greater than -7 because it is on the positive side of the number line, while -7 is on the negative side.

(iii) 0 and 8: 8 is greater than 0 because it is on the positive side of the number line, while 0 is the origin.

(iv) 0 and -3: 0 is greater than -3 because it is closer to the positive side of the number line, and in absolute terms, 0 is greater than -3.

So, summarizing: (i) -5 is greater than -7 (ii) 5 is greater than -7 (iii) 8 is greater than 0 (iv) 0 is greater than -3

To find the other integer when the sum of two integers is given, you subtract one of the integers from the sum to find the other integer.

Let's denote the other integer as xx.

Given: One integer is -122. The sum of the two integers is 238.

We can set up the equation: x+(−122)=238x+(−122)=238

To solve for xx, add 122 to both sides of the equation: x=238+122x=238+122 x=360x=360

So, the other integer is x=360

To find the other integer when the sum of two integers is given, you subtract one of the integers from the sum to find the other integer.

Let's denote the other integer as xx.

Given: One integer is 172. The sum of the two integers is -223.

We can set up the equation: x+172=−223x+172=−223

To solve for xx, subtract 172 from both sides of the equation: x=−223−172x=−223−172 x=−395x=−395

So, the other integer is x=−395x=−395.

If aa is the predecessor of bb, it means that aa is one less than bb.

So, we have: a=b−1a=b−1

To find a−ba−b, substitute the value of aa from the above equation: a−b=(b−1)−ba−b=(b−1)−b a−b=b−1−ba−b=b−1−b a−b=−1a−b=−1

So, a−b=−1a−b=−1.

Let's fill in the blanks with < or > to make the statements true:

(i) 3 > 0 (because 3 is greater than 0)

(ii) 0 > -8 (because 0 is greater than -8)

(iii) -9 < -3 (because -9 is less than -3)

(iv) -3 < 3 (because -3 is less than 3)

So, summarizing: (i) 3 > 0 (ii) 0 > -8 (iii) -9 < -3 (iv) -3 < 3

To arrange the given integers in ascending order, we simply need to reorder them from smallest to largest:

(i) -8, 0, -5, 5, 4, -1 Arranged in ascending order: -8, -5, -1, 0, 4, 5

(ii) 3, -3, 4, -7, 0, -6, 2 Arranged in ascending order: -7, -6, -3, 0, 2, 3, 4

(iii) -1, -7, 8, -3, 0, 3, 17 Arranged in ascending order: -7, -3, -1, 0, 3, 8, 17

(iv) 15, 19, -10, -7, 6, -6 Arranged in ascending order: -10, -7, -6, 6, 15, 19

So, the integers in ascending order for each case are: (i) -8, -5, -1, 0, 4, 5 (ii) -7, -6, -3, 0, 2, 3, 4 (iii) -7, -3, -1, 0, 3, 8, 17 (iv) -10, -7, -6, 6, 15, 19

To arrange the given integers in descending order, we reorder them from largest to smallest:

(i) -5, -3, 8, 15, 0, -2 Arranged in descending order: 15, 8, 0, -2, -3, -5

(ii) 12, 23, -11, 0, 7, 6 Arranged in descending order: 23, 12, 7, 6, 0, -11

So, the integers in descending order for each case are: (i) 15, 8, 0, -2, -3, -5 (ii) 23, 12, 7, 6, 0, -11

To solve this, we first find the sum of each pair and then subtract the sum of the first pair from the sum of the second pair.

Let's denote the pairs as follows:

Pair 1: -1250 and 1138 Pair 2: 1136 and -1272

Sum of Pair 1: -1250 + 1138 = -112 Sum of Pair 2: 1136 + (-1272) = -136

Now, we subtract the sum of Pair 1 from the sum of Pair 2: -136 - (-112) = -136 + 112 = -24

So, the result is -24.

To solve this, we first find the sum of 233 and -147, then subtract -284 from that sum.

Sum of 233 and -147: 233 + (-147) = 86

Now, we subtract -284 from 86: 86 - (-284) = 86 + 284 = 370

So, the result is 370.