I have 3 years of experience teaching for 6th standard students in a reputed school am very much fond of solving problems and explaining experiments...
Very successful and satisfying.
I love to teach students as I feel that every child has a special capability to prove and excel in life Only correct guidance is important. Please...
Do you need help in finding the best teacher matching your requirements?
Post your requirement nowI am an experienced and passionate teacher. I completed my MSc. in 1988 from Regional Engineering College Trichy. And my Bed 2013 Indra Gandhi National...
I started teaching 20 yrs back when the parents of my students insisted me to teach for higher classes also. I love teaching because my students...
I am a private tutor for classes 1st - 8th. I have being giving private tuition since June 2024. I am currently pursuing 12th grade but with self...
Personally connected with students so enhanced their skills in a holistic way .
I help students to follow their curriculum specially designed for them.In my guidance children learn to read, write and become numerate.Provides notes...
I am teaching from past 1 year I'm giving online tuition And hom tuition I have chemistry degree from mumbai university. My key skills are students...
I had a experience of 8 years as home tutor, and I use practical oriented methods to students.Generally I tried to increase creative and analytical...
Deepthi attended Class 6 Tuition
"Rajalakshmi is a very knowledgeable and competent teacher. She understands the needs..."
Nirmala attended Class 6 Tuition
"I met Ms. Roslin for my 7th std son's maths & science tuition classes. I have started..."
Seema attended Class 6 Tuition
"He has deep knowledge about the subjects. He taught me in Std VIIth as well as in..."
Tapan attended Class 6 Tuition
"please call"
Padma attended Class 6 Tuition
"Her approach&attitude"
Soumyadeep attended Class 6 Tuition
"Shalini is extremely efficient and caring while teaching the child.She takes time..."
Sindhu attended Class 6 Tuition
"its very early to comment about class as my son attended only 1 class.but i liked..."
Sindhu attended Class 6 Tuition
"personalized attention ,at a time only 2 kids ,and good environment "
Ask a Question
Post a LessonAnswered on 23 Feb Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables
Sadika
Let's denote: Length of the rectangle = 2332 of its breadth Breadth of the rectangle = xx cm
Then, we can express the length of the rectangle in terms of its breadth: Length=23×BreadthLength=32×Breadth Length=23×xLength=32×x Length=2x3Length=32x
Now, we can calculate the area of the rectangle: Area=Length×BreadthArea=Length×Breadth Area=(2x3)×xArea=(32x)×x Area=2x23Area=32x2
So, the area of the rectangle is 2x2332x2 square centimeters.
Answered on 23 Feb Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables
Sadika
If there are xx rows of chairs and each row contains x2x2 chairs, then the total number of chairs can be found by multiplying the number of rows by the number of chairs in each row.
Given: Number of rows (xx) Number of chairs in each row (x2x2)
Total number of chairs = Number of rows * Number of chairs in each row Total number of chairs = x×x2x×x2
So, the total number of chairs is x3x3.
Answered on 23 Feb Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables
Sadika
If there are x2x2 rows of chairs and each row contains 2×2x22×2x2 chairs, then the total number of chairs can be found by multiplying the number of rows by the number of chairs in each row.
Given: Number of rows (x2x2) Number of chairs in each row (2×2x2=4x22×2x2=4x2)
Total number of chairs = Number of rows * Number of chairs in each row Total number of chairs = x2×4x2x2×4x2
So, the total number of chairs in the room is 4x44x4.
Answered on 23 Feb Learn CBSE/Class 6/Maths/algebra/Conversion of Statement to Algebraic Expression
Sadika
Sure, here are two equations for which 22 is the solution:
When x=2x=2: 2−4=−22−4=−2 −2=−2−2=−2
When y=2y=2: 2×24=142×2=1 44=144=1 1=11=1
In both equations, 22 is the solution.
Answered on 23 Feb Learn CBSE/Class 6/Maths/algebra/Conversion of Statement to Algebraic Expression
Sadika
Here's an example of an equation whose solution is not a whole number:
2x+1=52x+1=5
To solve for xx, we need to isolate it: 2x=5−12x=5−1 2x=42x=4 x=42x=24 x=2x=2
So, the solution to this equation is x=2x=2, which is a whole number.
Let me provide another example:
3x−2=73x−2=7
To solve for xx, we need to isolate it: 3x=7+23x=7+2 3x=93x=9 x=93x=39 x=3x=3
In this equation, the solution is also a whole number.
Let's try another example:
2x+3=72x+3=7
To solve for xx, we need to isolate it: 2x=7−32x=7−3 2x=42x=4 x=42x=24 x=2x=2
Once again, the solution is a whole number.
It seems that I provided examples where the solution is a whole number. Let me adjust:
2x+1.5=52x+1.5=5
To solve for xx: 2x=5−1.52x=5−1.5 2x=3.52x=3.5 x=3.52x=23.5 x=1.75x=1.75
In this equation, the solution x=1.75x=1.75 is not a whole number.
Ask a Question