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algebra

algebra relates to CBSE/Class 6/Maths

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1
Deepashree Class 6 Tuition trainer in Bangalore Featured
Basaveshwara Nagar, Bangalore
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12 yrs of Exp
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I have 3 years of experience teaching for 6th standard students in a reputed school am very much fond of solving problems and explaining experiments...

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S. Hemaa Class 6 Tuition trainer in Bangalore Featured
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I am Ravi Shankar Kumar, I run my own coaching institute. I have more than five years of experience in teaching English in classes 9, 10, 11, and...

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Debamitra G. Class 6 Tuition trainer in Delhi Featured
C R Park, Delhi
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5 yrs of Exp
250per hour
Classes: Class 6 Tuition, Class 8 Tuition and more.

I love to teach students as I feel that every child has a special capability to prove and excel in life Only correct guidance is important. Please...

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Indira S. Class 6 Tuition trainer in Papanasam Featured
Arundavapuram, Papanasam
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I am an experienced and passionate teacher. I completed my MSc. in 1988 from Regional Engineering College Trichy. And my Bed 2013 Indra Gandhi National...

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Latika R C. Class 6 Tuition trainer in Bangalore Featured
Lower Palace Orchid, Bangalore
18 yrs of Exp
500per hour
Classes: Class 6 Tuition, Spoken English and more.

Summary Successful English, Hindi and Math Teacher with expertise in building engaging lesson plans and communicating ideas to foster student comprehension....

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Vanshika P. Class 6 Tuition trainer in Karnal Featured
Jundla, Karnal
250per hour
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I am a private tutor for classes 1st - 8th. I have being giving private tuition since June 2024. I am currently pursuing 12th grade but with self...

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Debdeep B. Class 6 Tuition trainer in Bangalore Featured
J P Nagar, Bangalore
14 yrs of Exp
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Priyangsu Biswas Class 6 Tuition trainer in Avadi Featured
Koilpathagai Road Junction Avadi, Avadi
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Classes: Class 6 Tuition, Class 10 Tuition and more.

Let's start learning English literature. It's easy and amazing.

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Jayshree R. Class 6 Tuition trainer in Faridabad Featured
Sector 23, Faridabad
20 yrs of Exp
250per hour
Classes: Class 6 Tuition, Class I-V Tuition and more.

I am a tutor by simplifying math concepts while coaching students to think critically to solve problems.I conducted tests regularly which led to an...

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Answered on 23/02/2024 Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To find Rahul's total score in English and Hindi, you simply add his scores in both subjects. Given: English score = 80 Hindi score = x Total score = English score + Hindi score Total score = 80 + x So, Rahul's total score in the two subjects is 80 + x. read more

To find Rahul's total score in English and Hindi, you simply add his scores in both subjects.

Given: English score = 80 Hindi score = x

Total score = English score + Hindi score Total score = 80 + x

So, Rahul's total score in the two subjects is 80 + x.

 
 
 
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Answered on 23/02/2024 Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To find out how much distance Rohit covers in yy steps, you simply multiply the distance covered in one step (xx centimeters) by the number of steps (yy). Given: Distance covered in one step (xx) = xx centimeters Number of steps (yy) = yy Distance covered = Distance covered in one step * Number of... read more

To find out how much distance Rohit covers in yy steps, you simply multiply the distance covered in one step (xx centimeters) by the number of steps (yy).

Given: Distance covered in one step (xx) = xx centimeters Number of steps (yy) = yy

Distance covered = Distance covered in one step * Number of steps Distance covered = xx * yy

So, Rohit covers x×yx×y centimeters in yy steps.

 
 
 
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Answered on 23/02/2024 Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To determine the total weight of xx apples and yy oranges, you'll need to multiply the weight of each type of fruit by the respective quantity and then sum the results. Given: Weight of one apple (aa) = 75 grams Weight of one orange (oo) = 40 grams Quantity of apples (xx) Quantity of oranges (yy) Total... read more

To determine the total weight of xx apples and yy oranges, you'll need to multiply the weight of each type of fruit by the respective quantity and then sum the results.

Given: Weight of one apple (aa) = 75 grams Weight of one orange (oo) = 40 grams Quantity of apples (xx) Quantity of oranges (yy)

Total weight = (Weight of one apple * Quantity of apples) + (Weight of one orange * Quantity of oranges) Total weight = (75×x)+(40×y)(75×x)+(40×y)

So, the total weight of xx apples and yy oranges is 75x+40y75x+40y grams.

 
 
 
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Answered on 23/02/2024 Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To determine the total cost of xx pencils and yy fountain pens, you'll multiply the cost of each item by the respective quantity and then sum the results. Given: Cost of one pencil (pp) = Rs 2 Cost of one fountain pen (ff) = Rs 15 Quantity of pencils (xx) Quantity of fountain pens (yy) Total... read more

To determine the total cost of xx pencils and yy fountain pens, you'll multiply the cost of each item by the respective quantity and then sum the results.

Given: Cost of one pencil (pp) = Rs 2 Cost of one fountain pen (ff) = Rs 15 Quantity of pencils (xx) Quantity of fountain pens (yy)

Total cost = (Cost of one pencil * Quantity of pencils) + (Cost of one fountain pen * Quantity of fountain pens) Total cost = (2×x)+(15×y)(2×x)+(15×y)

So, the total cost of xx pencils and yy fountain pens is 2x+15y2x+15y rupees.

 
 

 
 
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Answered on 23/02/2024 Learn CBSE/Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

Let's denote: Length of the rectangle = 2332 of its breadth Breadth of the rectangle = xx cm Then, we can express the length of the rectangle in terms of its breadth: Length=23×BreadthLength=32×Breadth Length=23×xLength=32×x Length=2x3Length=32x Now, we can calculate the area... read more

Let's denote: Length of the rectangle = 2332 of its breadth Breadth of the rectangle = xx cm

Then, we can express the length of the rectangle in terms of its breadth: Length=23×BreadthLength=32×Breadth Length=23×xLength=32×x Length=2x3Length=32x

Now, we can calculate the area of the rectangle: Area=Length×BreadthArea=Length×Breadth Area=(2x3)×xArea=(32x)×x Area=2x23Area=32x2

So, the area of the rectangle is 2x2332x2 square centimeters.

 
 
 
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