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Post a LessonAnswered on 17/04/2024 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Some Applications of Trigonometry
Sadika
To find the height of the tower, we can use trigonometry.
Answered on 17/04/2024 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Some Applications of Trigonometry
Sadika
Let's denote the height of the flagstaff as h meters.
Answered on 17/04/2024 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Some Applications of Trigonometry
Sadika
Let's denote the height of the tower as h meters.
Answered on 17/04/2024 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Some Applications of Trigonometry
Sadika
To prove the given expression for the height of the cloud above the lake, let's consider the scenario described.
Answered on 17/04/2024 Learn CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Some Applications of Trigonometry
Sadika
Given:
We can form two right triangles to represent the situation.
For the top of the 8 m tall building: tan(30∘)=8dtan(30∘)=d8
For the bottom of the 8 m tall building: tan(45∘)=8dtan(45∘)=d8
We can solve these two equations simultaneously to find the values of hh and dd.
First, let's solve for dd using either equation (they are the same):
tan(30∘)=8dtan(30∘)=d8
13=8d3
1=d8
d=83d=83
Now, using the value of dd, we can find the height of the multi-storeyed building using either equation:
tan(30∘)=hdtan(30∘)=dh
13=h833
1=83
h
h=8h=8
So, the height of the multi-storeyed building is 8 meters, and the distance between the two buildings is 8383
meters.
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