Borkhera, Kota, India - 324001.
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Hindi Mother Tongue (Native)
English Proficient
Indian Institute of Science Education and Research Bhopal 2017
Bachelor of Science (B.Sc.)
Indian Institute of Science Education and Research Bhopal 2019
MSc in Chemistry
Borkhera, Kota, India - 324001
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Experience in School or College
Great experience. I taught Chemistry at school. At this young age, students are very energetic and curious. So I also learned new things. Also, I tried to develop new methods to teach students by being interactive so that they would not feel subject (Chemistry) as a burden.
4 out of 5 1 review
Hemant Kumar
"I am one of the former student of sir. I really enjoyed learning from him. I know it is all about getting good marks but you should also have a good grip on concepts and he is the one who can make sure of it. "
1. Which classes do you teach?
I teach Class 12 Tuition Classes.
2. Do you provide a demo class?
No, I don't provide a demo class.
3. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 19/06/2020 Learn CBSE/Class 11
First, you have to convert log(having base 10 in question) to the natural log by dividing by 2.303, so the question becomes as following-
Now you have to solve it using integration by parts. Integration by parts is done by using the formula given below
Consider
So
Since it is an indefinite integration, you have to add constant 'C.'
so the answer is
If in the question log is considered to be a natural log function then you don't need to divide the integration by 2.303.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Experience in School or College
Great experience. I taught Chemistry at school. At this young age, students are very energetic and curious. So I also learned new things. Also, I tried to develop new methods to teach students by being interactive so that they would not feel subject (Chemistry) as a burden.
4 out of 5 1 review
Hemant Kumar
"I am one of the former student of sir. I really enjoyed learning from him. I know it is all about getting good marks but you should also have a good grip on concepts and he is the one who can make sure of it. "
Answered on 19/06/2020 Learn CBSE/Class 11
First, you have to convert log(having base 10 in question) to the natural log by dividing by 2.303, so the question becomes as following-
Now you have to solve it using integration by parts. Integration by parts is done by using the formula given below
Consider
So
Since it is an indefinite integration, you have to add constant 'C.'
so the answer is
If in the question log is considered to be a natural log function then you don't need to divide the integration by 2.303.
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Borkhera, Kota 
