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Overview

Karan Khaitan conducts classes in BSc Tuition, BTech Tuition and Class 10 Tuition. Karan is located in Digvijaygram, Jamnagar. Karan takes at students Home and Regular Classes- at his Home. He has 6 years of teaching experience . Karan has completed Bachelor of Engineering (B.E.) from Iit roorkee in 2016. HeĀ is well versed in Hindi and English.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Iit roorkee 2016

Bachelor of Engineering (B.E.)

Address

Digvijaygram, Jamnagar, India - 361140

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Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

Board

CBSE, State, ICSE

CBSE Subjects taught

Mathematics, English, Science

ICSE Subjects taught

English, Chemistry, Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, English, Mathematics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

6

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Physics, Chemistry, English, Mathematics

CBSE Subjects taught

English, Chemistry, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Chemistry, Physics, English

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

6

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics, Chemistry, English

CBSE Subjects taught

English, Physics, Mathematics

Taught in School or College

No

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

6

BTech Branch

BTech Chemical Engineering

BTech Chemical subjects

Chemical Reaction Engineering, Chemical Engineering, Chemical Process Calculations

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

6

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Mathematics

BSc Mathematics Subjects

Calculus, Algebra

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, State and ICSE

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach BSc Tuition, BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 6 years.

Answers by Karan Khaitan (1)

Answered on 21/05/2020 Learn Tuition

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0 Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero. So all the... ...more

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx

Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz)  +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0

Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero. So all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1.

Answers 353 Comments
Dislike Bookmark

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

Board

CBSE, State, ICSE

CBSE Subjects taught

Mathematics, English, Science

ICSE Subjects taught

English, Chemistry, Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, English, Mathematics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

6

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Physics, Chemistry, English, Mathematics

CBSE Subjects taught

English, Chemistry, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Chemistry, Physics, English

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

6

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics, Chemistry, English

CBSE Subjects taught

English, Physics, Mathematics

Taught in School or College

No

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

6

BTech Branch

BTech Chemical Engineering

BTech Chemical subjects

Chemical Reaction Engineering, Chemical Engineering, Chemical Process Calculations

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

6

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Mathematics

BSc Mathematics Subjects

Calculus, Algebra

No Reviews yet!

Answers by Karan Khaitan (1)

Answered on 21/05/2020 Learn Tuition

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0 Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero. So all the... ...more

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx

Rearranging the terms: => 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz)  +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0

Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero. So all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1.

Answers 353 Comments
Dislike Bookmark

Karan Khaitan conducts classes in BSc Tuition, BTech Tuition and Class 10 Tuition. Karan is located in Digvijaygram, Jamnagar. Karan takes at students Home and Regular Classes- at his Home. He has 6 years of teaching experience . Karan has completed Bachelor of Engineering (B.E.) from Iit roorkee in 2016. HeĀ is well versed in Hindi and English.

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