Mansarovar, Jaipur, India - 302020.
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Hindi Mother Tongue (Native)
English Proficient
University of Sheffield 2018
Master of Arts (M.A.)
Mansarovar, Jaipur, India - 302020
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
7
Fees
₹ 1000.0 per hour
Board
CBSE, International Baccalaureate, ICSE
IB Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I am a Manager, Researcher and Educator with more than 5 years of experience in curriculum design and learner-centric instruction. My experience ranges from teaching Mathematics to students from diverse age groups to application of different approaches to provide effective learning solutions. I have worked on curriculum development at institutions like Adani Foundation and have also conducted training programmes for teachers at teacher training institutes. As an UrbanPro Online Mathematics Tutor, I am interested in helping students to achieve their full academic potential that could also contribute to their fututre career goals. Mathematics is one of the most important subjects these days in context of increasing technological development globally. I believe that students differ in their learning styles. Hence, understanding the preferred learning mode of students serves as the basis for providing effective student-oriented learning solutions. In my online tuitions, I also address the problems of students in Mathematics by emphasising on the Mathematical principles and on the simpler approaches to solve a particular problem.
Taught in School or College
Yes
1. Which school boards of Class 1-5 do you teach for?
CBSE, International Baccalaureate and ICSE
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class I-V Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 7 years.
Answered on 22/06/2019 Learn Tuition
Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution of given values, the answer would be 3xyz.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
7
Fees
₹ 1000.0 per hour
Board
CBSE, International Baccalaureate, ICSE
IB Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I am a Manager, Researcher and Educator with more than 5 years of experience in curriculum design and learner-centric instruction. My experience ranges from teaching Mathematics to students from diverse age groups to application of different approaches to provide effective learning solutions. I have worked on curriculum development at institutions like Adani Foundation and have also conducted training programmes for teachers at teacher training institutes. As an UrbanPro Online Mathematics Tutor, I am interested in helping students to achieve their full academic potential that could also contribute to their fututre career goals. Mathematics is one of the most important subjects these days in context of increasing technological development globally. I believe that students differ in their learning styles. Hence, understanding the preferred learning mode of students serves as the basis for providing effective student-oriented learning solutions. In my online tuitions, I also address the problems of students in Mathematics by emphasising on the Mathematical principles and on the simpler approaches to solve a particular problem.
Taught in School or College
Yes
Answered on 22/06/2019 Learn Tuition
Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution of given values, the answer would be 3xyz.
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