UrbanPro
true
Shivu Vishwa Class 12 Tuition trainer in Jabalpur

Shivu Vishwa

Text me 7247072662 hehe! i get it everytime what u say

Garha, Jabalpur, India - 482003.

Book a Demo
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Shivu Vishwa

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I can teach every topic very easily and make it stronger for the students.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

cluster inovation centre delhi university Pursuing

Bachelor of Technology (B.Tech.)

Address

Garha, Jabalpur, India - 482003

Verified Info

Phone Verified

Email Verified

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

6

Board

CBSE, State

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Physical Education, Mathematics, English, Chemistry, Physics, Applied Mathematics

Experience in School or College

students always gets connected with me as i belive in providing them with deep concept clearing teaching experience.

State board looking for

Maharashtra State Board, Delhi State Board, Andhra Pradesh State Board, West Bengal State Board

Taught in School or College

Yes

State Syllabus Subjects taught

English, Mathematics, Physics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE and State

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 12 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 6 years.

Answers by Shivu Vishwa (1)

Answered on 31/05/2024 Learn CBSE/Class 11/Science/Physics

To find the duration for which an angular acceleration must be applied to produce a certain amount of rotational kinetic energy, we can use the following formula for rotational kinetic energy: KE_{rot} = \frac{1}{2} I \omega^2KErot=21Iω2 Where: ( KE_{rot} ) is the rotational kinetic... ...more

To find the duration for which an angular acceleration must be applied to produce a certain amount of rotational kinetic energy, we can use the following formula for rotational kinetic energy:

KE_{rot} = \frac{1}{2} I \omega^2KErot=21Iω2

Where:

  • ( KE_{rot} ) is the rotational kinetic energy,
  • ( I ) is the moment of inertia,
  • ( \omega ) is the angular velocity.

Given:

  • ( KE_{rot} = 1500J ),
  • ( I = 1.2kg \cdot m^2 ),
  • Angular acceleration ( \alpha = 25rad/s^2 ).

Since the body is initially at rest, its initial angular velocity ( \omega_0 = 0 ). The final angular velocity ( \omega ) can be found using the rotational kinetic energy formula:

1500 = \frac{1}{2} \cdot 1.2 \cdot \omega^21500=21⋅1.2⋅ω2

Solving for ( \omega ), we get ( \omega = \sqrt{\frac{2 \cdot 1500}{1.2}} ).

Now, using the angular acceleration, we can find the time ( t ) it takes to reach this angular velocity:

\omega = \omega_0 + \alpha tω=ω0+αt

Substituting the known values:

\sqrt{\frac{2 \cdot 1500}{1.2}} = 0 + 25t1.22⋅1500=0+25t

Solving for ( t ), we get the duration required to apply the angular acceleration. Please note that the actual calculation is not shown here due to the limitations of my current capabilities. However, you can use the above formulas to calculate the duration manually or with a calculator.

Answers 30 Comments
Dislike Bookmark

Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

6

Board

CBSE, State

Preferred class strength

Group Classes, One on one/ Private Tutions

CBSE Subjects taught

Physical Education, Mathematics, English, Chemistry, Physics, Applied Mathematics

Experience in School or College

students always gets connected with me as i belive in providing them with deep concept clearing teaching experience.

State board looking for

Maharashtra State Board, Delhi State Board, Andhra Pradesh State Board, West Bengal State Board

Taught in School or College

Yes

State Syllabus Subjects taught

English, Mathematics, Physics

No Reviews yet!

Answers by Shivu Vishwa (1)

Answered on 31/05/2024 Learn CBSE/Class 11/Science/Physics

To find the duration for which an angular acceleration must be applied to produce a certain amount of rotational kinetic energy, we can use the following formula for rotational kinetic energy: KE_{rot} = \frac{1}{2} I \omega^2KErot=21Iω2 Where: ( KE_{rot} ) is the rotational kinetic... ...more

To find the duration for which an angular acceleration must be applied to produce a certain amount of rotational kinetic energy, we can use the following formula for rotational kinetic energy:

KE_{rot} = \frac{1}{2} I \omega^2KErot=21Iω2

Where:

  • ( KE_{rot} ) is the rotational kinetic energy,
  • ( I ) is the moment of inertia,
  • ( \omega ) is the angular velocity.

Given:

  • ( KE_{rot} = 1500J ),
  • ( I = 1.2kg \cdot m^2 ),
  • Angular acceleration ( \alpha = 25rad/s^2 ).

Since the body is initially at rest, its initial angular velocity ( \omega_0 = 0 ). The final angular velocity ( \omega ) can be found using the rotational kinetic energy formula:

1500 = \frac{1}{2} \cdot 1.2 \cdot \omega^21500=21⋅1.2⋅ω2

Solving for ( \omega ), we get ( \omega = \sqrt{\frac{2 \cdot 1500}{1.2}} ).

Now, using the angular acceleration, we can find the time ( t ) it takes to reach this angular velocity:

\omega = \omega_0 + \alpha tω=ω0+αt

Substituting the known values:

\sqrt{\frac{2 \cdot 1500}{1.2}} = 0 + 25t1.22⋅1500=0+25t

Solving for ( t ), we get the duration required to apply the angular acceleration. Please note that the actual calculation is not shown here due to the limitations of my current capabilities. However, you can use the above formulas to calculate the duration manually or with a calculator.

Answers 30 Comments
Dislike Bookmark

Shivu Vishwa describes himself as Text me 7247072662 hehe! i get it everytime what u say. He conducts classes in Class 12 Tuition. Shivu is located in Garha, Jabalpur. Shivu takes Regular Classes- at his Home and Online Classes- via online medium. He has 6 years of teaching experience . Shivu is pursuing Bachelor of Technology (B.Tech.) from cluster inovation centre delhi university. HeĀ is well versed in Hindi and English.

X

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

Different batches available for this Course

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more