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Vanga Goutham Reddy Class 12 Tuition trainer in Hyderabad

Vanga Goutham Reddy

locationImg Begumpet, Hyderabad
1 yrs of Exp
students 1 student
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I am a engineering graduate student . I am good at all subjects. I am graduated from JNTUH. I want to teach the tuitions as I want to share my knowledge to other students.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Hindi Proficient

Education

Anurag group of institutions 2018

Bachelor of Technology (B.Tech.)

Address

Begumpet, Hyderabad, India - 500016

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Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

CBSE, State, ISC/ICSE, International Baccalaureate

Subjects taught

Economics, Engineering Graphics, Geography, Chemistry, Sanskrit, History, Computer Science, Mathematics, Biology, Political Science, Electronics, English, Telugu, Physics

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

History and Civics, Chemistry, English Literature, Social Science, Physics, Science, Sanskrit, Mathematics, Geography, English, Economic Application, Biology, Telugu

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ISC/ICSE

Subjects taught

Telugu, English, Economics, Mathematics, Biotechnology, Chemistry, Electronics, Computer Science, Engineering Graphics, Physics, History, Geography, Biology

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Electrical & Electronics subjects

Control Systems, Data Structures & Algorithms, Alternative Energy Sources, Electric Energy Systems, Switchgear And Protection, Electric Drives, High-Voltage Engineering, Power System Engineering, Power Electronics, Power System Protection, Regulation & Security, Discrete Fourier Transforms And Digital Filter Design, Electrical Circuit Analysis, Electromagnetic Theory, High-Voltage Direct Current (Hvdc) Transmission, Direct Energy Conversion, Embedded Processor Architecture, Design Of Embedded Controllers, Circuit Theory, Analog And Digital Communication, Applications of Digital Signal Processing (DSP), (Dc- Ac) Direct Current-Alternatiing Current System Interaction

BTech Branch

BTech Electrical & Electronics, BTech 1st Year Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech 1st Year subjects

Engineering Graphics, Engineering Mathematics (M1), Basic Electronics, Basic Electrical Technology, Engineering Chemistry, Advanced Mathematics (M2), Computer science, Engineering Physics, Environmental Studies

Reviews

No Reviews yet!

Answers by Vanga Goutham Reddy

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3

Ask a Question

Post a Lesson

Slope of normal and slope of tangent are perpendicular to each other.e.g., slope of normal x = 1 - a sinθdifferentiate x with respect to θ,dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)y = bcos²θdifferentiate y with respect to θ,dy/dθ = b. d(cos²θ)/dθ=... ...more

Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal 

x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)

dividing equations (2) by (1),

dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b

Answers 5 Comments
Dislike Bookmark

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4

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Post a Lesson

(x+a)× - x + x =0 (x+a) × - x + x = 0 (x+a) - ax² -ax² =0 2ax² + a²x + 2a²x + a³ -2ax² = 0 3a²x +a³ = 0 a² (3x + a) = 0 a != 0, ( 3x + a)= 0 3x = -a ...more

(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)]  =0

(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0

(x+a) [2ax + a²] - ax² -ax² =0

2ax² + a²x + 2a²x + a³ -2ax² = 0

3a²x +a³ = 0

a² (3x + a) = 0

a != 0, ( 3x + a)= 0

3x = -a

 

Answers 3 Comments
Dislike Bookmark
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Please select a Tag

Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

CBSE, State, ISC/ICSE, International Baccalaureate

Subjects taught

Economics, Engineering Graphics, Geography, Chemistry, Sanskrit, History, Computer Science, Mathematics, Biology, Political Science, Electronics, English, Telugu, Physics

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

History and Civics, Chemistry, English Literature, Social Science, Physics, Science, Sanskrit, Mathematics, Geography, English, Economic Application, Biology, Telugu

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ISC/ICSE

Subjects taught

Telugu, English, Economics, Mathematics, Biotechnology, Chemistry, Electronics, Computer Science, Engineering Graphics, Physics, History, Geography, Biology

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Electrical & Electronics subjects

Control Systems, Data Structures & Algorithms, Alternative Energy Sources, Electric Energy Systems, Switchgear And Protection, Electric Drives, High-Voltage Engineering, Power System Engineering, Power Electronics, Power System Protection, Regulation & Security, Discrete Fourier Transforms And Digital Filter Design, Electrical Circuit Analysis, Electromagnetic Theory, High-Voltage Direct Current (Hvdc) Transmission, Direct Energy Conversion, Embedded Processor Architecture, Design Of Embedded Controllers, Circuit Theory, Analog And Digital Communication, Applications of Digital Signal Processing (DSP), (Dc- Ac) Direct Current-Alternatiing Current System Interaction

BTech Branch

BTech Electrical & Electronics, BTech 1st Year Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech 1st Year subjects

Engineering Graphics, Engineering Mathematics (M1), Basic Electronics, Basic Electrical Technology, Engineering Chemistry, Advanced Mathematics (M2), Computer science, Engineering Physics, Environmental Studies

No Reviews yet!

Answers by Vanga Goutham Reddy

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3

Ask a Question

Post a Lesson

Slope of normal and slope of tangent are perpendicular to each other.e.g., slope of normal x = 1 - a sinθdifferentiate x with respect to θ,dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)y = bcos²θdifferentiate y with respect to θ,dy/dθ = b. d(cos²θ)/dθ=... ...more

Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal 

x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)

dividing equations (2) by (1),

dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b

Answers 5 Comments
Dislike Bookmark

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4

Ask a Question

Post a Lesson

(x+a)× - x + x =0 (x+a) × - x + x = 0 (x+a) - ax² -ax² =0 2ax² + a²x + 2a²x + a³ -2ax² = 0 3a²x +a³ = 0 a² (3x + a) = 0 a != 0, ( 3x + a)= 0 3x = -a ...more

(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)]  =0

(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0

(x+a) [2ax + a²] - ax² -ax² =0

2ax² + a²x + 2a²x + a³ -2ax² = 0

3a²x +a³ = 0

a² (3x + a) = 0

a != 0, ( 3x + a)= 0

3x = -a

 

Answers 3 Comments
Dislike Bookmark
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