Begumpet, Hyderabad, India - 500016.
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Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State, International Baccalaureate, ISC/ICSE, CBSE
IB Subjects taught
Mathematics, Physics, English, Economics, Computer Science, Biology, History, Chemistry, Geography
ISC/ICSE Subjects taught
Physics, English, Mathematics, Computer Science, Chemistry, History, Geography, Economics
CBSE Subjects taught
Engineering Graphics, Physics, Chemistry, Geography, Political Science, Mathematics, Economics, History
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Electronics, Sanskrit, Economics, English, Engineering Graphics, Geography, Mathematics, Telugu, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, State, CBSE
CBSE Subjects taught
Science, English, Mathematics, Sanskrit, Social science, Telugu
ICSE Subjects taught
Physics, English, Geography, Chemistry, Biology, Economic Application, Mathematics, History and Civics, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Social Science, English, Telugu, Mathematics, Science, Sanskrit
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, ISC/ICSE, CBSE
ISC/ICSE Subjects taught
Physics, Biology, English, Mathematics, Chemistry, Geography, Economics
CBSE Subjects taught
Computer Science, English, Biotechnology, Chemistry, Geography, Physics, Economics, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Electronics, Economics, English, Engineering Graphics, Geography, Mathematics, Biology, History, Telugu, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Electric Drives, Design Of Embedded Controllers, Electrical Circuit Analysis, Analog And Digital Communication, Data Structures & Algorithms, Direct Energy Conversion, High-Voltage Engineering, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Direct Current (Hvdc) Transmission, Electric Energy Systems, Applications of Digital Signal Processing (DSP), Control Systems, Discrete Fourier Transforms And Digital Filter Design, Embedded Processor Architecture, Electromagnetic Theory, Switchgear And Protection, Power System Engineering, Power Electronics, Circuit Theory, Power System Protection, Regulation & Security, Alternative Energy Sources
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Mathematics (M1), Advanced Mathematics (M2), Basic Electronics, Engineering Physics, Basic Electrical Technology, Environmental Studies, Engineering Chemistry, Computer science, Engineering Graphics
1. Which school boards of Class 12 do you teach for?
State, International Baccalaureate, ISC/ICSE and others
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State, International Baccalaureate, ISC/ICSE, CBSE
IB Subjects taught
Mathematics, Physics, English, Economics, Computer Science, Biology, History, Chemistry, Geography
ISC/ICSE Subjects taught
Physics, English, Mathematics, Computer Science, Chemistry, History, Geography, Economics
CBSE Subjects taught
Engineering Graphics, Physics, Chemistry, Geography, Political Science, Mathematics, Economics, History
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Electronics, Sanskrit, Economics, English, Engineering Graphics, Geography, Mathematics, Telugu, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, State, CBSE
CBSE Subjects taught
Science, English, Mathematics, Sanskrit, Social science, Telugu
ICSE Subjects taught
Physics, English, Geography, Chemistry, Biology, Economic Application, Mathematics, History and Civics, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Social Science, English, Telugu, Mathematics, Science, Sanskrit
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, ISC/ICSE, CBSE
ISC/ICSE Subjects taught
Physics, Biology, English, Mathematics, Chemistry, Geography, Economics
CBSE Subjects taught
Computer Science, English, Biotechnology, Chemistry, Geography, Physics, Economics, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Electronics, Economics, English, Engineering Graphics, Geography, Mathematics, Biology, History, Telugu, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Electric Drives, Design Of Embedded Controllers, Electrical Circuit Analysis, Analog And Digital Communication, Data Structures & Algorithms, Direct Energy Conversion, High-Voltage Engineering, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Direct Current (Hvdc) Transmission, Electric Energy Systems, Applications of Digital Signal Processing (DSP), Control Systems, Discrete Fourier Transforms And Digital Filter Design, Embedded Processor Architecture, Electromagnetic Theory, Switchgear And Protection, Power System Engineering, Power Electronics, Circuit Theory, Power System Protection, Regulation & Security, Alternative Energy Sources
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Mathematics (M1), Advanced Mathematics (M2), Basic Electronics, Engineering Physics, Basic Electrical Technology, Environmental Studies, Engineering Chemistry, Computer science, Engineering Graphics
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
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