Begumpet, Hyderabad, India - 500016.
1
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Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, State, CBSE, ISC/ICSE
IB Subjects taught
Mathematics, History, Physics, Chemistry, Biology, English, Economics, Computer Science, Geography
ISC/ICSE Subjects taught
Mathematics, Economics, History, Geography, Physics, Chemistry, Computer Science, English
CBSE Subjects taught
Geography, Chemistry, Mathematics, Economics, Engineering Graphics, Physics, Political Science, History
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Physics, Geography, Mathematics, Chemistry, Engineering Graphics, Electronics, Economics, English, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Mathematics, Science, English, Sanskrit, Social science, Telugu
ICSE Subjects taught
Mathematics, English, Economic Application, History and Civics, English Literature, Physics, Biology, Chemistry, Geography
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Sanskrit, Social Science, English, Telugu, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics, Economics, Geography, Physics, Chemistry, English, Biology
CBSE Subjects taught
Geography, Biology, Chemistry, Mathematics, Economics, Biotechnology, Computer Science, English, Physics
Taught in School or College
No
State Syllabus Subjects taught
History, Physics, Geography, Mathematics, Chemistry, Biology, Engineering Graphics, Electronics, Economics, English, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Analog And Digital Communication, Control Systems, Electric Drives, High-Voltage Direct Current (Hvdc) Transmission, Electromagnetic Theory, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, Applications of Digital Signal Processing (DSP), Power System Protection, Regulation & Security, Data Structures & Algorithms, Design Of Embedded Controllers, Direct Energy Conversion, Power Electronics, Discrete Fourier Transforms And Digital Filter Design, Circuit Theory, Embedded Processor Architecture, Power System Engineering, Switchgear And Protection, Alternative Energy Sources, Electrical Circuit Analysis, High-Voltage Engineering, Electric Energy Systems
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Chemistry, Basic Electrical Technology, Environmental Studies, Engineering Mathematics (M1), Engineering Graphics, Basic Electronics, Computer science, Advanced Mathematics (M2), Engineering Physics
1. Which school boards of Class 12 do you teach for?
International Baccalaureate, State, CBSE and others
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, State, CBSE, ISC/ICSE
IB Subjects taught
Mathematics, History, Physics, Chemistry, Biology, English, Economics, Computer Science, Geography
ISC/ICSE Subjects taught
Mathematics, Economics, History, Geography, Physics, Chemistry, Computer Science, English
CBSE Subjects taught
Geography, Chemistry, Mathematics, Economics, Engineering Graphics, Physics, Political Science, History
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Physics, Geography, Mathematics, Chemistry, Engineering Graphics, Electronics, Economics, English, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Mathematics, Science, English, Sanskrit, Social science, Telugu
ICSE Subjects taught
Mathematics, English, Economic Application, History and Civics, English Literature, Physics, Biology, Chemistry, Geography
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Sanskrit, Social Science, English, Telugu, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics, Economics, Geography, Physics, Chemistry, English, Biology
CBSE Subjects taught
Geography, Biology, Chemistry, Mathematics, Economics, Biotechnology, Computer Science, English, Physics
Taught in School or College
No
State Syllabus Subjects taught
History, Physics, Geography, Mathematics, Chemistry, Biology, Engineering Graphics, Electronics, Economics, English, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Analog And Digital Communication, Control Systems, Electric Drives, High-Voltage Direct Current (Hvdc) Transmission, Electromagnetic Theory, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, Applications of Digital Signal Processing (DSP), Power System Protection, Regulation & Security, Data Structures & Algorithms, Design Of Embedded Controllers, Direct Energy Conversion, Power Electronics, Discrete Fourier Transforms And Digital Filter Design, Circuit Theory, Embedded Processor Architecture, Power System Engineering, Switchgear And Protection, Alternative Energy Sources, Electrical Circuit Analysis, High-Voltage Engineering, Electric Energy Systems
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Chemistry, Basic Electrical Technology, Environmental Studies, Engineering Mathematics (M1), Engineering Graphics, Basic Electronics, Computer science, Advanced Mathematics (M2), Engineering Physics
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
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