Begumpet, Hyderabad, India - 500016.
1
Details verified of Vanga Goutham Reddy✕
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Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, State, International Baccalaureate, CBSE
IB Subjects taught
English, History, Chemistry, Mathematics, Physics, Computer Science, Geography, Economics, Biology
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry, Economics, Geography, English, History, Computer Science
CBSE Subjects taught
Political Science, History, Physics, Geography, Economics, Engineering Graphics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Economics, English, Geography, Electronics, Sanskrit, Engineering Graphics, Physics, Telugu, Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Telugu, Mathematics, Science, Sanskrit, Social science
ICSE Subjects taught
Geography, History and Civics, English Literature, Physics, Biology, Chemistry, English, Mathematics, Economic Application
Taught in School or College
No
State Syllabus Subjects taught
Social Science, English, Sanskrit, Telugu, Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Physics, Biology, Mathematics, Chemistry, Economics, Geography, English
CBSE Subjects taught
Biotechnology, Physics, English, Computer Science, Geography, Economics, Chemistry, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Economics, English, Geography, Biology, Electronics, Engineering Graphics, History, Physics, Telugu, Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
High-Voltage Direct Current (Hvdc) Transmission, Electric Drives, Electric Energy Systems, Analog And Digital Communication, Design Of Embedded Controllers, Direct Energy Conversion, Power System Protection, Regulation & Security, Switchgear And Protection, Alternative Energy Sources, Circuit Theory, Discrete Fourier Transforms And Digital Filter Design, Electromagnetic Theory, Power Electronics, Applications of Digital Signal Processing (DSP), (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Engineering, Embedded Processor Architecture, Control Systems, Power System Engineering, Data Structures & Algorithms, Electrical Circuit Analysis
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Environmental Studies, Computer science, Basic Electrical Technology, Engineering Graphics, Engineering Mathematics (M1), Advanced Mathematics (M2), Engineering Chemistry, Basic Electronics, Engineering Physics
1. Which school boards of Class 12 do you teach for?
ISC/ICSE, State, International Baccalaureate and others
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, State, International Baccalaureate, CBSE
IB Subjects taught
English, History, Chemistry, Mathematics, Physics, Computer Science, Geography, Economics, Biology
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry, Economics, Geography, English, History, Computer Science
CBSE Subjects taught
Political Science, History, Physics, Geography, Economics, Engineering Graphics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Economics, English, Geography, Electronics, Sanskrit, Engineering Graphics, Physics, Telugu, Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
English, Telugu, Mathematics, Science, Sanskrit, Social science
ICSE Subjects taught
Geography, History and Civics, English Literature, Physics, Biology, Chemistry, English, Mathematics, Economic Application
Taught in School or College
No
State Syllabus Subjects taught
Social Science, English, Sanskrit, Telugu, Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Physics, Biology, Mathematics, Chemistry, Economics, Geography, English
CBSE Subjects taught
Biotechnology, Physics, English, Computer Science, Geography, Economics, Chemistry, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Economics, English, Geography, Biology, Electronics, Engineering Graphics, History, Physics, Telugu, Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
High-Voltage Direct Current (Hvdc) Transmission, Electric Drives, Electric Energy Systems, Analog And Digital Communication, Design Of Embedded Controllers, Direct Energy Conversion, Power System Protection, Regulation & Security, Switchgear And Protection, Alternative Energy Sources, Circuit Theory, Discrete Fourier Transforms And Digital Filter Design, Electromagnetic Theory, Power Electronics, Applications of Digital Signal Processing (DSP), (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Engineering, Embedded Processor Architecture, Control Systems, Power System Engineering, Data Structures & Algorithms, Electrical Circuit Analysis
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Environmental Studies, Computer science, Basic Electrical Technology, Engineering Graphics, Engineering Mathematics (M1), Advanced Mathematics (M2), Engineering Chemistry, Basic Electronics, Engineering Physics
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
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