Begumpet, Hyderabad, India - 500016.
1
Details verified of Vanga Goutham Reddy✕
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Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, ISC/ICSE, State, CBSE
IB Subjects taught
Physics, Chemistry, Geography, Economics, Mathematics, Biology, English, History, Computer Science
ISC/ICSE Subjects taught
English, Economics, Computer Science, Chemistry, Mathematics, Geography, History, Physics
CBSE Subjects taught
Political Science, Physics, Mathematics, Chemistry, Economics, Engineering Graphics, Geography, History
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Engineering Graphics, Electronics, Economics, Telugu, English, Mathematics, Chemistry, Physics, Geography
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, ICSE, State
CBSE Subjects taught
Science, Social science, Telugu, Sanskrit, English, Mathematics
ICSE Subjects taught
History and Civics, Economic Application, Chemistry, English, English Literature, Mathematics, Physics, Biology, Geography
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Science, Telugu, English, Mathematics, Social Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
English, Economics, Chemistry, Mathematics, Biology, Geography, Physics
CBSE Subjects taught
Physics, English, Chemistry, Mathematics, Economics, Biology, Geography, Biotechnology, Computer Science
Taught in School or College
No
State Syllabus Subjects taught
Engineering Graphics, Electronics, Economics, Telugu, English, History, Mathematics, Chemistry, Physics, Geography, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Power Electronics, Power System Engineering, Control Systems, Direct Energy Conversion, Electromagnetic Theory, Electric Drives, Discrete Fourier Transforms And Digital Filter Design, Embedded Processor Architecture, Switchgear And Protection, Alternative Energy Sources, Design Of Embedded Controllers, Electric Energy Systems, Electrical Circuit Analysis, Data Structures & Algorithms, Analog And Digital Communication, Applications of Digital Signal Processing (DSP), Circuit Theory, Power System Protection, Regulation & Security, High-Voltage Engineering, High-Voltage Direct Current (Hvdc) Transmission
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Basic Electronics, Basic Electrical Technology, Advanced Mathematics (M2), Engineering Chemistry, Engineering Mathematics (M1), Environmental Studies, Engineering Physics, Computer science, Engineering Graphics
1. Which school boards of Class 12 do you teach for?
International Baccalaureate, ISC/ICSE, State and others
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, ISC/ICSE, State, CBSE
IB Subjects taught
Physics, Chemistry, Geography, Economics, Mathematics, Biology, English, History, Computer Science
ISC/ICSE Subjects taught
English, Economics, Computer Science, Chemistry, Mathematics, Geography, History, Physics
CBSE Subjects taught
Political Science, Physics, Mathematics, Chemistry, Economics, Engineering Graphics, Geography, History
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Engineering Graphics, Electronics, Economics, Telugu, English, Mathematics, Chemistry, Physics, Geography
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, ICSE, State
CBSE Subjects taught
Science, Social science, Telugu, Sanskrit, English, Mathematics
ICSE Subjects taught
History and Civics, Economic Application, Chemistry, English, English Literature, Mathematics, Physics, Biology, Geography
Taught in School or College
No
State Syllabus Subjects taught
Sanskrit, Science, Telugu, English, Mathematics, Social Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
English, Economics, Chemistry, Mathematics, Biology, Geography, Physics
CBSE Subjects taught
Physics, English, Chemistry, Mathematics, Economics, Biology, Geography, Biotechnology, Computer Science
Taught in School or College
No
State Syllabus Subjects taught
Engineering Graphics, Electronics, Economics, Telugu, English, History, Mathematics, Chemistry, Physics, Geography, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Power Electronics, Power System Engineering, Control Systems, Direct Energy Conversion, Electromagnetic Theory, Electric Drives, Discrete Fourier Transforms And Digital Filter Design, Embedded Processor Architecture, Switchgear And Protection, Alternative Energy Sources, Design Of Embedded Controllers, Electric Energy Systems, Electrical Circuit Analysis, Data Structures & Algorithms, Analog And Digital Communication, Applications of Digital Signal Processing (DSP), Circuit Theory, Power System Protection, Regulation & Security, High-Voltage Engineering, High-Voltage Direct Current (Hvdc) Transmission
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Basic Electronics, Basic Electrical Technology, Advanced Mathematics (M2), Engineering Chemistry, Engineering Mathematics (M1), Environmental Studies, Engineering Physics, Computer science, Engineering Graphics
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
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