Osmania University, Hyderabad, India - 500007.
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Telugu Mother Tongue (Native)
Hindi Basic
English Basic
Chaitanya Bharathi Institute of Technology Pursuing
Bachelor of Engineering (B.E.)
Osmania University Pursuing
Masters of Engineering
Government Polytechnic Masab Tank 2018
Diploma in Civil Engineering
Osmania University, Hyderabad, India - 500007
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Engineering Diploma 1st Year, Civil Engineering Diploma
Engineering Diploma Subject
English, Engineering Mechanics, Communication Skills, Basic Physics, Engineering Mathematics, Workshop Drawing, Basic Math
Civil Engineering Diploma Subject
Mechanics of Structures, Surveying, Concrete Technology, Design of Structures, Water shade Management, Geo Technical Engineering, Transportation Engineering, Highway Engineering, Hydraulics, Theory Of Structures, Environment Engineering, Building Drawing, Irrigation Engineering, Applied Mathematics (CE and ME Group), Building Construction, Computer Aided Drawing, Estimating & Costing, Micro Irrigation, Design Of Steel Structures, Architectural Practices and Interior Design
Type of class
Crash Course, Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
1. Which Engineering Diploma branches do you tutor for?
Engineering Diploma 1st Year and Civil Engineering Diploma
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Engineering Diploma Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Engineering Diploma 1st Year, Civil Engineering Diploma
Engineering Diploma Subject
English, Engineering Mechanics, Communication Skills, Basic Physics, Engineering Mathematics, Workshop Drawing, Basic Math
Civil Engineering Diploma Subject
Mechanics of Structures, Surveying, Concrete Technology, Design of Structures, Water shade Management, Geo Technical Engineering, Transportation Engineering, Highway Engineering, Hydraulics, Theory Of Structures, Environment Engineering, Building Drawing, Irrigation Engineering, Applied Mathematics (CE and ME Group), Building Construction, Computer Aided Drawing, Estimating & Costing, Micro Irrigation, Design Of Steel Structures, Architectural Practices and Interior Design
Type of class
Crash Course, Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
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