Sector 119, Noida, India - 201307.
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Bengali Mother Tongue (Native)
English Proficient
Hindi Proficient
Nagpur University 2014
Master of Science (M.Sc.)
Sector 119, Noida, India - 201307
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2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
3
BSc Chemistry Subjects
Polymer Chemistry, Spectroscopy, Organic Qualitative & Quantitative Analysis, Organic Functional Groups, Concepts In Inorganic Chemistry, Hydrocarbons And Stereochemistry
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
BSc Branch
BSc Chemistry
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry
Teaching Experience in detail in Class 12 Tuition
I have 5 years teaching experience on all branch of chemistry like physical, organic and inorganic chemistry. During taking classes I observed that students were fear about solving mathematical problem, especially in physical chemistry. Here my responsibility was to provide proper technique how they can easily understand the problem and save themselves from the fear of solving mathematical problems. Another students fears were on different types of organic reaction and their mechanism. In this case at first I clear their basic concept about reaction and how the reaction proceeds following particular pathway. During my B.Sc. I provide chemistry tuition for three years, state board level in West Bengal. During my M.Sc. from Nagpur university I provide chemistry tuition for two years, CBSE level. Now I pursuing my PhD from DRDE, Gwalior and looking some class 11 & 12 level students for providing sound chemistry tuition.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry
Teaching Experience in detail in Class 11 Tuition
The interesting experience about my class 11 Tuition was my first class on structure of atom. Here starting from Dalton's atomic theory via Bohr's atomic model to quantum mechanical model of atom. Most of the students are confused about all these things and started fearing the chapter. But I try to explain this chapter in front of the students just like a story. So that they can easily grab the whole matter. Another chapter is Chemical Thermodynamics, there are limitless fear in the students mind about this chapter. This problem was being solved with the help of diagramtical explanation and provide different techniques how to remember the related terminology.
1. Do you have any prior teaching experience?
No
2. Which classes do you teach?
I teach BSc Tuition, Class 11 Tuition and Class 12 Tuition Classes.
3. Do you provide a demo class?
No, I don't provide a demo class.
4. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula
x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)
For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula
x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)
For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.
Answered on 17/03/2019 Learn Tuition Fee
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
Answered on 17/03/2019 Learn Tuition
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
3
BSc Chemistry Subjects
Polymer Chemistry, Spectroscopy, Organic Qualitative & Quantitative Analysis, Organic Functional Groups, Concepts In Inorganic Chemistry, Hydrocarbons And Stereochemistry
Type of class
Regular Classes
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
BSc Branch
BSc Chemistry
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry
Teaching Experience in detail in Class 12 Tuition
I have 5 years teaching experience on all branch of chemistry like physical, organic and inorganic chemistry. During taking classes I observed that students were fear about solving mathematical problem, especially in physical chemistry. Here my responsibility was to provide proper technique how they can easily understand the problem and save themselves from the fear of solving mathematical problems. Another students fears were on different types of organic reaction and their mechanism. In this case at first I clear their basic concept about reaction and how the reaction proceeds following particular pathway. During my B.Sc. I provide chemistry tuition for three years, state board level in West Bengal. During my M.Sc. from Nagpur university I provide chemistry tuition for two years, CBSE level. Now I pursuing my PhD from DRDE, Gwalior and looking some class 11 & 12 level students for providing sound chemistry tuition.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry
Teaching Experience in detail in Class 11 Tuition
The interesting experience about my class 11 Tuition was my first class on structure of atom. Here starting from Dalton's atomic theory via Bohr's atomic model to quantum mechanical model of atom. Most of the students are confused about all these things and started fearing the chapter. But I try to explain this chapter in front of the students just like a story. So that they can easily grab the whole matter. Another chapter is Chemical Thermodynamics, there are limitless fear in the students mind about this chapter. This problem was being solved with the help of diagramtical explanation and provide different techniques how to remember the related terminology.
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula
x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)
For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula
x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)
For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.
Answered on 17/03/2019 Learn Tuition Fee
Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
Answered on 17/03/2019 Learn Tuition
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