Sector 105 Laxman Garden, Gurgaon, India - 122006.
Details verified of Manish Kumar Sharma✕
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Hindi Proficient
English Proficient
DGCG 2012
Bachelor of Science (B.Sc.)
Mahrishi Dayanand University, Rohtak 2014
Bachelor of Education (B.Ed.)
KITM, Gurgaon 2016
Master of Science (M.Sc.)
Sector 105 Laxman Garden, Gurgaon, India - 122006
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
4
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Experience in School or College
I am a PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Experience in School or College
I am PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
CBSE, ICSE, State
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I am a PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
1. Which school boards of Class 12 do you teach for?
ISC/ICSE, State and CBSE
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 4 years.
Answered on 28/06/2019 Learn Tuition
Here, this is not a question for proving any identity this question is for finding the value....for finding..
X2+Y2+Z2=XY+YZ+ZX
X2+y2+z2 -xy - yz -zx = 0
Now multiplying both side with (x+y+z), we get
(x+y+z)(x2+y2+z2 - xy -yz - zx) = 0
Now, solving this, we get finally
X3+y3+z3-3xyz = 0
Then, x3+y3+z3 = 3xyz
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
4
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Experience in School or College
I am a PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
ISC/ICSE, State, CBSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Experience in School or College
I am PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
CBSE, ICSE, State
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I am a PGT Mathematics in DRONACHARYA SR SEC SCHOOL
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Answered on 28/06/2019 Learn Tuition
Here, this is not a question for proving any identity this question is for finding the value....for finding..
X2+Y2+Z2=XY+YZ+ZX
X2+y2+z2 -xy - yz -zx = 0
Now multiplying both side with (x+y+z), we get
(x+y+z)(x2+y2+z2 - xy -yz - zx) = 0
Now, solving this, we get finally
X3+y3+z3-3xyz = 0
Then, x3+y3+z3 = 3xyz
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