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BSc Tuition > BSc Tuition in Gurgaon > Bindia H.

Bindia H. BSc Tuition trainer in Gurgaon

Bindia H.

Electronics & Communications Expert

Sector 23, Gurgaon, India - 122001.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Core Subjects: Digital Signal Processing, Wireless Communications, Electrical Circuit Analysis, Electronic Devices, VLSI <br/> <br/>Application Software: MATLAB, Optisystem, Orcad 16.0, Xilinx ISE <br/> <br/>Scripting Languages: Unix Shell Scripting, Perl Scripting Programming Languages: Verilog, C, Visual C++, Visual Basic, PL/SQL <br/> <br/>WireLine INSITE Quad for HALLIBURTON <br/>â?ª Developed/ Enhanced tools & applications using MFC, Visual C++ as front end & Ms-Access as back end. <br/>â?ª Worked on InSite Core, Plotting & assisted in the maintenance of Data Logs. <br/> <br/>File Transfer System for RLL <br/>â?ª Developed console based User Interface to allow two remote machines to transfer files between them using C Language. <br/>â?ª Maintained Login & File Transfer Logs. <br/> <br/>National Science Olympiad subject topper for Chemistry.

Languages Spoken

Punjabi Proficient

English Proficient

Hindi Proficient

Education

Guru Nanak Dev University, Amritsar Pursuing

Master of Engineering - Master of Technology (M.E./M.Tech.)

Address

Sector 23, Gurgaon, India - 122001

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Teaches

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

2

BSc Electronics Subjects

Data Structures, Digital Electronics, Signals and Systems, Network Analysis, Semiconductor Devices, Analog Electronics, Analog Communication, Digital Communication, Fundamental of Programming Languages, Mathematics

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

BSc Branch

BSc Electronics

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Electrical & Electronics subjects

Electrical Circuit Analysis, Analog And Digital Communication

BTech Electrical & Communication

Information Theory and Coding, Optical Fiber Communication, Semiconductor Device Physics, Satellite Communication, Analog Electronics, Digital Image Processing, Wireless Communication, Communication Networks, Object Oriented Programming, Data Structures and Algorithms, Mobile Communication, (VLSI/ULSI) Very Large Scale Integration Process Technology, Analog Communication, Electronic Circuit Design, Digital Communication, Digital Electronics

BTech Branch

BTech Electrical & Communication Engineering

BTech Instrumentation subjects

Digital Signal Processing

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

MATLAB Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in MATLAB Training

2

Reviews

No Reviews yet!

FAQs

1. Do you have any prior teaching experience?

No

2. Which classes do you teach?

I teach BSc Tuition, BTech Tuition and MATLAB Classes.

3. Do you provide a demo class?

Yes, I provide a free demo class.

4. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Bindia H. (1)

Answered on 25/06/2019 Learn Tuition

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

Given: x² +y² +z² = xy + yz + zx This can be re-written as: x² +y² +z² - xy - yz - zx = 0 Multiplying both sides by (x + y + z) : (x + y + z) (x² +y² +z² - xy – yz – zx) = 0 Simplifying: x³ + xy² + xz² - x²y - xyz -zx²... ...more

Given:  x² +y² +z² =  xy + yz + zx

This can be re-written as: x² +y² +z² -  xy - yz - zx = 0

Multiplying both sides by (x + y + z) :  (x + y + z) (x² +y² +z² -  xy – yz – zx) = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + y³ + z³ - 3xyz = 0 or  x³ + y³ + z³ = 3xyz

Answers 278 Comments
Dislike Bookmark

Contact

Teaches

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

2

BSc Electronics Subjects

Data Structures, Digital Electronics, Signals and Systems, Network Analysis, Semiconductor Devices, Analog Electronics, Analog Communication, Digital Communication, Fundamental of Programming Languages, Mathematics

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

BSc Branch

BSc Electronics

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Electrical & Electronics subjects

Electrical Circuit Analysis, Analog And Digital Communication

BTech Electrical & Communication

Information Theory and Coding, Optical Fiber Communication, Semiconductor Device Physics, Satellite Communication, Analog Electronics, Digital Image Processing, Wireless Communication, Communication Networks, Object Oriented Programming, Data Structures and Algorithms, Mobile Communication, (VLSI/ULSI) Very Large Scale Integration Process Technology, Analog Communication, Electronic Circuit Design, Digital Communication, Digital Electronics

BTech Branch

BTech Electrical & Communication Engineering

BTech Instrumentation subjects

Digital Signal Processing

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

MATLAB Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in MATLAB Training

2

No Reviews yet!

Answers by Bindia H. (1)

Answered on 25/06/2019 Learn Tuition

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

Given: x² +y² +z² = xy + yz + zx This can be re-written as: x² +y² +z² - xy - yz - zx = 0 Multiplying both sides by (x + y + z) : (x + y + z) (x² +y² +z² - xy – yz – zx) = 0 Simplifying: x³ + xy² + xz² - x²y - xyz -zx²... ...more

Given:  x² +y² +z² =  xy + yz + zx

This can be re-written as: x² +y² +z² -  xy - yz - zx = 0

Multiplying both sides by (x + y + z) :  (x + y + z) (x² +y² +z² -  xy – yz – zx) = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + y³ + z³ - 3xyz = 0 or  x³ + y³ + z³ = 3xyz

Answers 278 Comments
Dislike Bookmark

Contact

Bindia H. describes herself as Electronics & Communications Expert. She conducts classes in BSc Tuition, BTech Tuition and MATLAB. Bindia is located in Sector 23, Gurgaon. Bindia takes at students Home, Regular Classes- at her Home and Online Classes- via online medium. She has 2 years of teaching experience . Bindia is pursuing Master of Engineering - Master of Technology (M.E./M.Tech.) from Guru Nanak Dev University, Amritsar. She is well versed in Punjabi, English and Hindi.

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