UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true

Class 12 Tuition > Class 12 Tuition in Guntur > Naveena K.

Naveena K. Class 12 Tuition trainer in Guntur/>

Naveena K.

Navabharath Nagar, Guntur, India - 522006.

Contact
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Naveena K.✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am an engineer who loves Mathematics and has a passion for teaching it. I am giving online classes for now.

Through out my life, I taught Math to my fellow undergraduates from different majors, my friends preparing for Entrance exams, my siblings through their high school and also on an online tutoring site as a tutor during my undergrad. As a tutor, I simplified math concepts while coaching students to think critically to solve problems. I appreciated and gave assurance to boost student's self-confidence and self-esteem. I cultivated a fun and interesting learning environment which, encouraged questions and discussions.

I can teach various Math topics like Algebra, Geometry, Mensuration, Trigonometry, Calculus, Differentiation, Integration and many more in Basic/Intermediate/Advanced levels.

P.S: I have also been among the top students in National Olympiad in Math. I was very enthusiastic and learnt ABACUS too.

Languages Spoken

Telugu Mother Tongue (Native)

Hindi Proficient

English Proficient

Education

National Institute of Technology, Calicut 2018

Bachelor of Technology (B.Tech.)

Address

Navabharath Nagar, Guntur, India - 522006

Verified Info

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, NIOS, IGCSE, CBSE, International Baccalaureate, State

Subjects taught

Mathematics, Geography, Hindi, Social science, Philosophy, Environmental Management, English, Education, Physical Education, Statistics, Telugu, Logic, Physics, Home Science, Computer Science, Sociology, EVS, History, Electronics

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

ISC/ICSE, NIOS, IGCSE and others

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 12 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Naveena K. (1)

Answered on 22/06/2020 Learn Tuition

<p>5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z</p>

Rearrange the equation as (x^2 + y^2 + z^2) + 4*(x^2 + y^2 + z^2) - 4*(xy + yz + zx) = 0 Now rearrange this again such that (x^2 + y^2 + z^2) + 2 = 0 Since a squared number is always positive, the above equation leads us to (x^2 + y^2 + z^2) = 0 and (x-y)^2 + (y-z)^2 + (z-x)^2 = 0, which means x=y=z=0... ...more

Rearrange the equation as (x^2 + y^2 + z^2) + 4*(x^2 + y^2 + z^2) - 4*(xy + yz + zx) = 0

Now rearrange this again such that (x^2 + y^2 + z^2) + 2[(x-y)^2 + (y-z)^2 + (z-x)^2 ] = 0

Since a squared number is always positive, the above equation leads us to (x^2 + y^2 + z^2) = 0 and (x-y)^2 + (y-z)^2 + (z-x)^2 = 0, which means x=y=z=0 is the ONLY possible solution.

Answers 353 Comments
Dislike Bookmark

Contact

Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, NIOS, IGCSE, CBSE, International Baccalaureate, State

Subjects taught

Mathematics, Geography, Hindi, Social science, Philosophy, Environmental Management, English, Education, Physical Education, Statistics, Telugu, Logic, Physics, Home Science, Computer Science, Sociology, EVS, History, Electronics

Taught in School or College

No

No Reviews yet!

Answers by Naveena K. (1)

Answered on 22/06/2020 Learn Tuition

<p>5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z</p>

Rearrange the equation as (x^2 + y^2 + z^2) + 4*(x^2 + y^2 + z^2) - 4*(xy + yz + zx) = 0 Now rearrange this again such that (x^2 + y^2 + z^2) + 2 = 0 Since a squared number is always positive, the above equation leads us to (x^2 + y^2 + z^2) = 0 and (x-y)^2 + (y-z)^2 + (z-x)^2 = 0, which means x=y=z=0... ...more

Rearrange the equation as (x^2 + y^2 + z^2) + 4*(x^2 + y^2 + z^2) - 4*(xy + yz + zx) = 0

Now rearrange this again such that (x^2 + y^2 + z^2) + 2[(x-y)^2 + (y-z)^2 + (z-x)^2 ] = 0

Since a squared number is always positive, the above equation leads us to (x^2 + y^2 + z^2) = 0 and (x-y)^2 + (y-z)^2 + (z-x)^2 = 0, which means x=y=z=0 is the ONLY possible solution.

Answers 353 Comments
Dislike Bookmark

Contact

Naveena K. conducts classes in Class 12 Tuition. Naveena is located in Navabharath Nagar, Guntur. Naveena takes Online Classes- via online medium. Naveena has completed Bachelor of Technology (B.Tech.) from National Institute of Technology, Calicut in 2018. She is well versed in Hindi, English and Telugu.

X

Share this Profile

Recommended Profiles

Chavapati Abdul Kalam photo

Chavapati Abdul Kalam

Chavapati Abdul Kalam photo Navabharath Nagar, Guntur

GM Academy

GM Academy photo Navabharath Nagar, Guntur

Dharani K. photo

Dharani K.

Dharani K. photo Navabharath Nagar, Guntur

Rajeswari P.

Rajeswari P. photo Navabharath Nagar, Guntur

Mani photo

Mani

Mani photo Navabharath Nagar, Guntur

Mamidala S

Mamidala S photo Navabharath Nagar, Guntur

Also have a look at

Learn More

NCERT Class 12 Solutions CBSE Syllabus for Class 12 Chapter 1 - Electric Charges and Fields Chapter 2 - Electrostatic Potential and Capacitance Chapter 3 - Current Electricity Chapter 4 - Moving Charges and Magnetism Chapter 5 - Magnetism and Matter Chapter 6 - Electromagnetic Induction Chapter 7 - Alternating Current Chapter 8 - Electromagnetic Waves

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

✕

Different batches available for this Course

Book a Free Demo

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2025 All Rights Reserved