Janakpuri, Delhi, India - 110058.
Details verified of Vikash Kumar Singh✕
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Hindi Mother Tongue (Native)
English Proficient
B.N.M Institute of technology 2016
Bachelor of Engineering (B.E.)
Janakpuri, Delhi, India - 110058
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
CBSE, ISC/ICSE
Subjects taught
Biology, English, Economics, Physics, Hindi, Political Science, Mathematics, Geography, Chemistry, History
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
ICSE, CBSE
Subjects taught
Biology, History and Civics, Social Science, Chemistry, Computer Application, Hindi, Geography, Physics, English, Science, Computer Practices, Economics, Information and Comunication Technology, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
CBSE, ISC/ICSE
Subjects taught
Physics, Hindi, Chemistry, Geography, Computer Science, Political Science, History
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
CBSE and ISC/ICSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 5 years.
Answered on 09/07/2019 Learn Tuition
Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
a2+b2 =468
4a-4b=24, a-b=6
(a-b)2= a2+b2-2ab=36
468-2ab=36
432=2ab
ab=216
And a-b =6
So a=18 ,b=12
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
CBSE, ISC/ICSE
Subjects taught
Biology, English, Economics, Physics, Hindi, Political Science, Mathematics, Geography, Chemistry, History
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
ICSE, CBSE
Subjects taught
Biology, History and Civics, Social Science, Chemistry, Computer Application, Hindi, Geography, Physics, English, Science, Computer Practices, Economics, Information and Comunication Technology, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
CBSE, ISC/ICSE
Subjects taught
Physics, Hindi, Chemistry, Geography, Computer Science, Political Science, History
Taught in School or College
No
Answered on 09/07/2019 Learn Tuition
Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
a2+b2 =468
4a-4b=24, a-b=6
(a-b)2= a2+b2-2ab=36
468-2ab=36
432=2ab
ab=216
And a-b =6
So a=18 ,b=12
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Janakpuri, Delhi 
