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Engineering Entrance Coaching classes > Engineering Entrance Coaching in Jaipur > Pranjal Bhardvaj

Pranjal Bhardvaj Engineering Entrance trainer in Jaipur

Pranjal Bhardvaj

Lalkothi Jyothi Nagar, Jaipur, India - 302005.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

Hindi

English

Education

IIT Bombay Pursuing

Bachelor of Technology (B.Tech.)

Address

Lalkothi Jyothi Nagar, Jaipur, India - 302005

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Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

1

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Integrated Coaching, IIT JEE Mains Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Physics , Maths

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Engineering Entrance Coaching Class.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 1 year.

Contact

Answers by Pranjal Bhardvaj (2)

Answered on 29/06/2017 Learn Tuition/Class XI-XII Tuition (PUC)

What is value Tan360?

If 360 is in degrees, tan360 = 0, else if it is in radians convert it in degrees by 360*180/pi. then you get tan360 = -3.38. Usually if unspecified it is considered in radians.
Answers 145 Comments
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Answered on 29/06/2017 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration... ...more
A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?

First of all, that is not the correct unit for acceleration. Assuming you meant to say 12m/s^2, Since the elevator is descending at an acceleration greater than acceleration due to gravity, the block will have a relative acceleration of 2.2m/s^2 in the opposite direction as the block will start free... ...more
First of all, that is not the correct unit for acceleration. Assuming you meant to say 12m/s^2, Since the elevator is descending at an acceleration greater than acceleration due to gravity, the block will have a relative acceleration of 2.2m/s^2 in the opposite direction as the block will start free falling. Using the equation S = u*t + 0.5*a*t*t yields S = 0*0.2 + 0.5*(-2.2)*0.2*0.2 = 0.044m in the opposite direction of the elevator.
Answers 25 Comments
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Contact

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

1

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Integrated Coaching, IIT JEE Mains Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Physics , Maths

No Reviews yet!

Answers by Pranjal Bhardvaj (2)

Answered on 29/06/2017 Learn Tuition/Class XI-XII Tuition (PUC)

What is value Tan360?

If 360 is in degrees, tan360 = 0, else if it is in radians convert it in degrees by 360*180/pi. then you get tan360 = -3.38. Usually if unspecified it is considered in radians.
Answers 145 Comments
Dislike Bookmark

Answered on 29/06/2017 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration... ...more
A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?

First of all, that is not the correct unit for acceleration. Assuming you meant to say 12m/s^2, Since the elevator is descending at an acceleration greater than acceleration due to gravity, the block will have a relative acceleration of 2.2m/s^2 in the opposite direction as the block will start free... ...more
First of all, that is not the correct unit for acceleration. Assuming you meant to say 12m/s^2, Since the elevator is descending at an acceleration greater than acceleration due to gravity, the block will have a relative acceleration of 2.2m/s^2 in the opposite direction as the block will start free falling. Using the equation S = u*t + 0.5*a*t*t yields S = 0*0.2 + 0.5*(-2.2)*0.2*0.2 = 0.044m in the opposite direction of the elevator.
Answers 25 Comments
Dislike Bookmark

Contact

Pranjal Bhardvaj conducts classes in Engineering Entrance Coaching. Pranjal is located in Lalkothi Jyothi Nagar, Jaipur. Pranjal takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 1 years of teaching experience . Pranjal is pursuing Bachelor of Technology (B.Tech.) from IIT Bombay. He is well versed in Hindi and English.

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