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Abhishek Gupta Class 11 Tuition trainer in Delhi

Abhishek Gupta

Mukherjee Nagar, Delhi, India - 110009.

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Overview

I am Abhishek Gupta, I am in b. Sc second-year student with chemistry honours. I completed my +2 then I started teaching in Kota. I teach physics, chemistry, mathematics, Hindi and English grammar for 9 to 12 state and code. Also, explain jee-mains and neet without a bio.

Languages Spoken

Hindi Mother Tongue (Native)

Education

SNS COLLEGE 2016

2nd PUC

Address

Mukherjee Nagar, Delhi, India - 110009

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics, Biology, Physics, Hindi

CBSE Subjects taught

Physics, Hindi, Mathematics, English, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics, Chemistry, Sanskrit, Hindi

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics, Biology, Physics, Hindi

CBSE Subjects taught

Physics, Hindi, Mathematics, English, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics, Chemistry, Sanskrit, Hindi

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

ISC/ICSE, State, CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Abhishek Gupta (5)

Answered on 10/12/2018 Learn CBSE/Class 12/Science/Chemistry/Unit VII: p - Block Elements +1 CBSE/Class 11/Science/Chemistry

So , borax is how to obtained. When high temperature conc. HCL is added to borax (Na2B4O7.10H2O) soluble H3BO3 Which is reduced. Na2B4O7(anhydrous) +2HCL(hot) - 2NaCl + H2B4O7 H2B4O7+5H2O - 4H3BO3 2H3BO3 - B2O3+ 3H2O(stonglst heated) B2O3+6K- 2B+3K2O In other way we can consider Mg,Na .so, B2O3+6Na... ...more

So , borax is how to obtained.

When high temperature conc. HCL is added to borax (Na2B4O7.10H2O) soluble H3BO3 Which is reduced.

Na2B4O7(anhydrous) +2HCL(hot)  - 2NaCl + H2B4O7

H2B4O7+5H2O -   4H3BO3

2H3BO3  -  B2O3+ 3H2O(stonglst heated)

B2O3+6K- 2B+3K2O 

In other way we can consider  Mg,Na .so,

B2O3+6Na - 2B+3NaO

Same same Mg then  2B and 3MgO formed.

Answers 1 Comments
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Answered on 10/12/2018 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals) +1 CBSE/Class 11/Science/Chemistry

Firat of all uses of these are respectively. 1.caustic soda- manufacture of paper ,soaps, detergent etc. 2.sodium carbonate- manufacture of glass ,paper ,soaps etc 3.lime soda- making cement,treat treaof drinking water
Answers 3 Comments
Dislike Bookmark

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics, Biology, Physics, Hindi

CBSE Subjects taught

Physics, Hindi, Mathematics, English, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics, Chemistry, Sanskrit, Hindi

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics, Biology, Physics, Hindi

CBSE Subjects taught

Physics, Hindi, Mathematics, English, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics, Chemistry, Sanskrit, Hindi

No Reviews yet!

Answers by Abhishek Gupta (5)

Answered on 10/12/2018 Learn CBSE/Class 12/Science/Chemistry/Unit VII: p - Block Elements +1 CBSE/Class 11/Science/Chemistry

So , borax is how to obtained. When high temperature conc. HCL is added to borax (Na2B4O7.10H2O) soluble H3BO3 Which is reduced. Na2B4O7(anhydrous) +2HCL(hot) - 2NaCl + H2B4O7 H2B4O7+5H2O - 4H3BO3 2H3BO3 - B2O3+ 3H2O(stonglst heated) B2O3+6K- 2B+3K2O In other way we can consider Mg,Na .so, B2O3+6Na... ...more

So , borax is how to obtained.

When high temperature conc. HCL is added to borax (Na2B4O7.10H2O) soluble H3BO3 Which is reduced.

Na2B4O7(anhydrous) +2HCL(hot)  - 2NaCl + H2B4O7

H2B4O7+5H2O -   4H3BO3

2H3BO3  -  B2O3+ 3H2O(stonglst heated)

B2O3+6K- 2B+3K2O 

In other way we can consider  Mg,Na .so,

B2O3+6Na - 2B+3NaO

Same same Mg then  2B and 3MgO formed.

Answers 1 Comments
Dislike Bookmark

Answered on 10/12/2018 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals) +1 CBSE/Class 11/Science/Chemistry

Firat of all uses of these are respectively. 1.caustic soda- manufacture of paper ,soaps, detergent etc. 2.sodium carbonate- manufacture of glass ,paper ,soaps etc 3.lime soda- making cement,treat treaof drinking water
Answers 3 Comments
Dislike Bookmark

Abhishek Gupta conducts classes in Class 11 Tuition and Class 12 Tuition. Abhishek is located in Mukherjee Nagar, Delhi. Abhishek takes at students Home. He has 2 years of teaching experience . Abhishek has completed 2nd PUC from SNS COLLEGE in 2016. HeĀ is well versed in Hindi.

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